Answer:
53 lies between 7.2² and 7.3²
Step-by-step explanation:
Estimating a root to the nearest tenth can be done a number of ways. The method shown here is to identify the tenths whose squares bracket the value of interest.
You have answered the questions of parts 1 to 3.
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<h3>4.</h3>
You are given that ...
7.2² = 51.84
7.3² = 53.29
This means 53 lies between 7.2² and 7.3², so √53 lies between 7.2 and 7.3.
53 is closer to 7.3², so √53 will be closer to 7.3 than to 7.2.
7.3 is a good estimate of √53 to the tenths place.
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<em>Additional comment</em>
For an integer n that is the sum of a perfect square (s²) and a remainder (r), the square root is between ...
s +r/(2s+1) < √n < s +r/(2s)
For n = 53 = 7² +4, this means ...
7 +4/15 < √53 < 7 +4/14
7.267 < √53 < 7.286
Either way, √53 ≈ 7.3.
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The root is actually equal to the continued fraction ...
Answer:
B decrease
Step-by-step explanation:
First, lets put the numbers in order from greatest to least.
10 9 9 8 6 4 4
Second, let's find the median without number 1. (The median is in bold.)
10 9 9 8 6 4 4
Third, let's add the number 1.
10 9 9 8 6 4 4 1
Fourth, let's find the median with the number 1.
10 9 9 8 6 4 4 1
Since there are two numbers in the middle let's find the average between them.
8+6=14
14/2= 7
Last, let's compare the two medians.
8>7
So when you add the number 1 the median decreases. So your answer is B decrease
Answer: The function is negative for all real values of x.where
x < -2.
Step-by-step explanation:
Because the values -4 and -6 are less than -2 which is the basis of the statement highlighted as the right one.
Answer:
ummm where is the question anyway?
<h3>
Answer: No, this isn't a function.</h3>
Why not? Focus on the two points (0,2) and (0,4)
We have the x value x = 0 show up twice. Any time x repeats itself like this, it leads to "not a function" as the result.
In other words, the input x = 0 leads to multiple outputs y = 2 and y = 4 at the same time. A function is only possible if every x input leads to exactly one y output.
If you are a visual learner, then plot all of the points on the same xy grid. Then notice how (0,2) and (0,4) fail the vertical line test to show we don't have a function.
Side note: The y values can repeat themselves in a function.
