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soldier1979 [14.2K]
3 years ago
12

Simplify 4/40 the fraction

Mathematics
2 answers:
pishuonlain [190]3 years ago
4 0
Welll to simplify 4/40 divide 4 by 4 to get 1 and 40 divided by 4 to get 10 to get 1/10
irakobra [83]3 years ago
4 0
4/40 can be simplified to 1/10 <u /><u>.Hope I Helped!!!!!!!!(Sorry about the underlines) ;)</u>
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Students heights in inches were obtained as part of a study and a frequency distribution was constructed with the first class ha
polet [3.4K]
The frequency of the second class is 6.

Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55.  This would put the second class at 56-61.  There are 6 data points in this set that would go in the second class.
8 0
3 years ago
X + y = 8 <br> how do i solve for x
IgorC [24]

Answer:

x = 8 - y

Step by step explaination:

==>x + y = 8

==> x = 8 - y

==> substract the value

==> Done

5 0
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Kryger [21]
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3 years ago
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I need help proving this ASAP
Ket [755]

Answer:

See explanation

Step-by-step explanation:

We want to show that:

\tan(x +  \frac{3\pi}{2} )  =  -   \cot \: x

One way is to use the basic double angle formula:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ \sin(x)  \cos( \frac{3\pi}{2} )  +   \cos(x)  \sin( \frac{3\pi}{2}) }{\cos(x)  \cos( \frac{3\pi}{2} )   -    \sin(x)  \sin( \frac{3\pi}{2}) }

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ \sin(x) ( 0)  +   \cos(x) (  - 1) }{\cos(x) (0)   -    \sin(x) (  - 1) }

We simplify further to get:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ 0  -   \cos(x) }{0 +    \sin(x) }

We simplify again to get;

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{- \cos(x) }{ \sin(x) }

This finally gives:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  -  \cot(x)

6 0
3 years ago
Without using a calculator, fill in the blanks with two consecutive integers to complete the following inequality ____ &lt; √134
puteri [66]

11 < \sqrt{134} < 12\\\\because\\\\11^2=121 < (\sqrt{134})^2=134 < 12^2=144

7 0
3 years ago
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