2 years ago

Evaluate 3^2 (6-2) times 4-6/3

Mathematics

1 answer:

dedylja [7]2 years ago

4 0

3^2(6-2)*(4-6)/3
=(9*4)*(-2/3)
=36*(-2)/3
= -72/3
= -24 (answer)

You might be interested in

Simplify. write the answer as a fraction. -21/51

Jlenok [28]

Answer:

i think the answer is -7/17

Step-by-step explanation:

hope it help :) i dont really good with fraction

3 0

3 years ago

HELPPPPPPPPPPP<br><br> WHAT IS 67+8,900+12+14+15????

Blababa [14]

Answer:

9,008

Step-by-step explanation:

67 + 12 = 79

14 + 15 = 29

79 + 29 = 108

8,900 + 108 = 9,008

plz mark me brainliest

3 0

2 years ago

Read 2 more answers

How do you prove a rectangle in geometry?

dedylja [7]

- The opposite sides are parallel and congruent. - The diagonals bisect each other.

- There are 4 right angles. - The diagonals are congruent.

- Show that both pairs of opposite sides are congruent.

6 0

3 years ago

Help is needed PLZZ!!!!!

Westkost [7]

Answer:

C. Moved all terms from left to right that doesn't contain y

Y=-6 +1/3x-3

Simplify

Y=1/3x-9

Step-by-step explanation:

6 0

2 years ago

Solve using Quadratic Formula <br>x^2 + 3x - 3 = 0

katrin [286]

Answer:

a= 1 , b= 3 , c= –3

$x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - 3 \frac{ + }{} {} \sqrt{ {3}^{2} - 4(1)( - 3)} }{2(1)} \\ = \frac{ - 3 \frac{ + }{} \sqrt{9 + 12} }{2} = \frac{ - 3 \frac{ + }{} \sqrt{21} }{2} \\ \\ x = \frac{ - 3 \frac{ + }{} \sqrt{21} }{2} \\ \\ x = 0.79 \\ x = - 3.79$

I hope I helped you^_^

4 0

2 years ago