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4 years ago

If 9/24 =3/x , then x is ___ a0.

2 answers:

6 0

$\dfrac{9}{24} = \dfrac{3}{x}$

Cross-Multiply:
$9x = 3 \times 24$

Evaluate:
$9x = 72$

Divide both sides by 9:
$x = 8$

Answer: x = 8

Eva8 [605]4 years ago

5 0

Is this your question

if $\frac{9}{24}$ = $\frac{3}{x}$ then x= _____?

we know that 3 goes into 9 three times to equal 3 because we are basically just simplifying here either way if we are simplifying by 3 then 3 goes into 24 eight times

x = 8

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Write 2847 correct to the nearest 100

Eduardwww [97]

It has to be 2800 hope it right

7 0

3 years ago

Please show full SOLUTIONS!! I WILL MARK BRAINLIEST FOR THE BEST ANSWER. THANKS

Molodets [167]

The orthocentre for the triangle ABC is (1.85, 5.88).

Triangle ABC has vertices at A(2, 8), B(6, 2) and C(-3, 2).

We need to use analytical geometry to determine the coordinates of the orthocentre.

<h3>How to find the orthocentre using analytical geometry?</h3>

Steps to find the orthocentre:

Step 1: First, we will find the slopes of any two sides of the triangle (say AC and AB).

Step 2: Next, we can find the slopes of the corresponding altitudes. Remember that if two lines are perpendicular to each other, they satisfy the following equation.

Step 3: Next, we will use the slope-point form of the equation of a straight line to find the equations of the lines that are coincident with the altitudes BE and AD.

Step 4: Next, we can solve the equations of BE and CF simultaneously to find their solution, which gives us the coordinates of the orthocentre H.

Now, the slope of AC=2-8/-3-2=6/5 and the slope of BE=5/6.

The slope of AB=2-8/6-2=-6/4=-3/2 and the slope of CF=-2/3

The slope of BE=y-2/x-6=5/6

⇒6x-5y-26=0----(1)

The slope of CF=y-2/x+3=-2/3

⇒-2x-3y=0----(2)

By solving (1) and(2), we get

y=26/14=13/7=1.85 and x=5.88

Therefore, the orthocentre for the triangle ABC is (1.85, 5.88).

To learn more about the orthocentre of the triangle visit:

brainly.com/question/2264608.

#SPJ1

8 0

2 years ago

Which point is on the circle centered at the origin with a radius of 5 units? Distance formula: StartRoot (x 2 minus x 1) square

Sergeeva-Olga [200]

Answer:

Option A) $(2,\sqrt{21})$

Step-by-step explanation:

The following information is missing in the question:

A. $(2,\sqrt{21})$

B. $(2,\sqrt{23})$

C. (2, 1)

D. (2, 3)

We are given the following in the question:

A circle centered at origin and radius 5 units.

We have to find the equation of a point that lies on the circle.

Let (x,y) lie on the circle.

Distance formula:

$d = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Putting

$(x_2,y_2) = (x,y)\\(x_1.y_1) = (0,0)\\d = 5$

We get,

$5 = \sqrt{(y-0)^2 + (x-0)^2}\\\sqrt{x^2+y^2}=5\\x^2+y^2 = 25$

is the required equation of point on the circle centered at the origin with a radius of 5 units.

The point $(2,\sqrt{21})$ satisfies the given equation.

Verification:

$(2)^2 + (\sqrt{21})^2\\=4 + 21\\=25$

Thus, $(2,\sqrt{21})$ lies on the circle centered at the origin with a radius of 5 units.

7 0

4 years ago

Read 2 more answers

The function fff is given in three equivalent forms. Which form most quickly reveals the zeros (or "roots") of the function? Cho

Mazyrski [523]

Answer:

(B) $f(x)=-3(x+1)(x-5)$

x=5

Step-by-step explanation:

Given the three equivalent forms of f(x):

$f(x)=-3(x-2)^2+27\\f(x)=-3(x+1)(x-5)\\f(x)=-3x^2+12x+15$

The form which most quickly reveals the zeros (or "roots") of f(x) is

(B) $f(x)=-3(x+1)(x-5)$

This is as a result of the fact that on equating to zero, the roots becomes immediately evident.

$f(x)=-3(x+1)(x-5)=0\\-3\neq 0\\Therefore:\\x+1=0$ or x-5=0\\The zeros are x=-1 or x=5$

Therefore, one of the zeros, x=5

3 0

3 years ago

Locate the point on the line segment between A(3, -5) and B(13, -15) given that the point is 4/5 of the way from A to B. Show yo

SVETLANKA909090 [29]

Answer:

C ( 11 , -11 )

Step-by-step explanation:

Solution:-

We are given two points in the cartesian coordinate system as:

A ( 3 , -5 ) B ( 13 , -15 )

The point C lies on the line segment from A to B. The ratio of segment given is:

AC / AB = 4 / 5

To solve such type of problems. We will use vector equation of line AC.

To form a vector equation of line representing AB. We will first determine the direction vector ( d ) that is parallel to the line AB as follows:

d = OB - OA

d = < 13 , -15 > - < 3 , -5 >

d = < 10 , -10 >

The fixed point on the line is taken. We will take point A. The vector equation of line from point A to point B is expressed as:

< x , y > = OA + s*d

< x , y > = < 3, -5 > + s* < 10 , -10 >

The above equation satisfies all the points that lies on the line AB. To determine the coordinates of ( C ). We will plug in the appropriate value of parameter ( s ) and evaluate.

So point C is 4/5 th the magnitude of the distance AB from A. Hence, s = 4/5 as follows:

< x , y > = < 3 , -5 > + ( 4/5 ) * < 10 , -10 >

< x , y > = < 3 , -5 > + < 8 , -8 >

< x , y > = < 11 , -11 > ... Answer

8 0

3 years ago