Plz help me!!!!!!!!!!!!!!

Mathematics

1 answer:

DanielleElmas [232]3 years ago

8 0

Answer:

$1.50 per ticket.

Step-by-step explanation:

If you were to divide the amount of money by the amount of tickets in each row then they would each come out as 1.50.

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Solve each equation for y (get into slope-intercept/y=mx + b form):

Gwar [14]

Answer:

Step-by-step explanation:

In order to do this we need to isolate y by performing the inverse operations on the other values like so...

a) 10x + 5y = 20 ... subtract 10x on both sides

5y = 20 - 10x ... divide both sides by 5

y = 4 - 2x ... we can move the 2x to the right to make it into y = mx + b

y = -2x + 4

b) 3x - 2y = 10 + 4x ... subtract 3x on both sides

-2y = 10 + x ... divide both sides by -2

y = -5 - 0.5x ... move -0.5 to the left so it matches y = mx + b

y = -0.5x - 5

3 0

3 years ago

Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .

Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of $F$ around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

$F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle$

Therefore,

$P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y$

Let's calculate the needed partial derivatives.

$P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0$

Thus,

$Q_x -P_y = 0 -2 = - 2$

Now, by the Green's theorem, we have

$\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x \Big|_{-3}^{4} = -42$