4(8+1); Peter is adding one marker to each box so we add 1 to 8 first because of order of operations (PEMDAS). There are 9 markers in each of the four boxes, 9 x 4 is 36 markers total
For this case we have the following points:
y = (- 2, 5)
z = (1, 3)
Therefore, the vector yz is given by:
yz = z - y = (1, 3) - (-2, 5)
yz = ((1 - (- 2)), (3-5))
yz = ((1 + 2), -2)
yz = (3, -2)
Then, the magnitude is given by:
lyzl = root ((3) ^ 2 + (-2) ^ 2)
lyzl = root (9 + 4)
lyzl = root (13)
Answer:
yz = (3, -2)
lyzl = root (13)
option A
<span>1. the sum of 12 and the quotient of 9 and a number
The responder's answer is not given but it can be 12 + (9 / n)
2. </span>the difference of 12 and the product of 9 and a number
The responder's answer would be <span>c. 12 – 9y
3</span>. the difference of 12 and the quotient of 9 and a number
The responder's answer would be <span>b. 12 – (9 ÷ y)
</span>
<span>4. 12 more than quotient of a 9 and number
</span>
The responder's answer would be<span> a. 12 + (9 ÷ y)</span>
Standard form is (y=x+n) *n=number* y=-3x+2
Answer:
y = 5
Step-by-step explanation:
cross-multiply:
6y = 30
y = 5
