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mixer [17]
3 years ago
10

How Do You Do The Math Questions

Mathematics
1 answer:
Ray Of Light [21]3 years ago
7 0
1.A 2.B hope this helps
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You take your favorite teacher out to lunch. The total
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Answer:

it would be 45 total with the 20%

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Lindsey's math certificate is 17 centimeters tall and 31 centimeters wide. Lindsey wants to put the certificate in a fancy frame
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 i believe it would be 96 dollars.

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The question is At the pet fair, there were42 dogs and 35 cats. The pets must be split into small groups so that there are the s
Lelechka [254]
42=2*3*7
35=5*7
their GCF is 7, so the cats and dogs must be split into 7 groups
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3 0
3 years ago
A line that passes through (-7, 5) has a slope of 1/2. Which is another point that the line passes through?
d1i1m1o1n [39]

Answer:

(1, 9)

Step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = \frac{1}{2} and (a, b) = (- 7, 5), hence

y - 5 = \frac{1}{2}(x + 7)

y - 5 = \frac{1}{2} x + \frac{7}{2}

y = \frac{1}{2} x + \frac{17}{2} ← equation of line

To find another point on the line choose any value of x and substitute into the equation for the corresponding y- coordinate

x = 1 : y = \frac{1}{2} + \frac{17}{2} = 9

Thus (1, 9) is another point that the line passes through


8 0
4 years ago
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p
tankabanditka [31]

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

6 0
4 years ago
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