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3 years ago

Which two hundred thousands is 391,360 between?

Mathematics

1 answer:

zhenek [66]3 years ago

6 0

Hi!

<h3>Hundred thousands are </h3>

100,000
200,000
300,000
400,000
500,000
600,000
700,000
800,000
900,000

<h3>Where is 391,360 on this? </h3>

100,000
200,000
300,000
391,360
400,000
500,000
600,000
700,000
800,000
900,000

<u>It's between 300,000 and 400,000. </u>

<h2>The answer is 300,000 and 400,000. </h2>

Hope this helps! :)

-Peredhel

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kolbaska11 [484]

Answer:

a) P(x) = 32000*1.04^x
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c) During year 7

Step-by-step explanation:

<u>Given</u>

Initial pay = $32000
Increase rate = 4%

a. <u>Formula</u>

P(x) = 32000*1.04^x

b. Year 5 is after 4 years, so we are looking for the value of P(4)

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2 years ago

Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x

Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

$y=a(x-h)^2+k$

(where (h, k) is the vertex)

Given:

vertex = (1, -108)

$\implies y=a(x-1)^2-108$

Given:

y-intercept = (0, -105)

$\implies a(0-1)^2-108=-105$

$\implies a(-1)^2=-105+108$

$\implies a=3$

Therefore:

$\implies y=3(x-1)^2-108$

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$\implies 3(x-1)^2-108=0$

$\implies 3(x-1)^2=108$

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$\implies x=7, x=-5$

Therefore, the x-intercepts are (7, 0) and (-5, 0)

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