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AfilCa [17]
3 years ago
12

What should u do if you have to find out the modal if we are using coulours

Mathematics
1 answer:
Ann [662]3 years ago
5 0
Gvgjggjhvhh. Ghb ftb. Cgn. Cv.
You might be interested in
Solve the following system of equations by substitution and select the correct answer below:
Alexxx [7]
Okay so for substitution, chose one of  of the equations to solve for x. Let's solve for the second one. So you have 2x-8y=32.
Start by adding 8y to both sides:
 2x=8y+32.
Then you have to get x by itself so you divide both sides by 2 which will give you:
 x=4y+16.

Now you have:
6x-4y=36
x=4y+16 (this was 2x-8y=32)

Now, plug in the second equation to the first one. You would do so by plugging in the second equation to where you see x. You would have:
6(4y+16)-4y=36

Now, multiply the 6 with the 4y and 16. you would then have:
24y+96-4y=36.

Now, combine your like terms to get:
20y+96=36
Then subtract 96 to both sides:
20y=-60
Then divide both sides so that you have y all by itself:
y=-30!

You now have the answer for y, so now plug what you got for y into the other equation: x+4y=16: 
x+4(-30)=60
Solve for x:
x-120=60 
add 120 to both sides:
x=180!
so Your answer is Y=-30 and X=180

I hope this helped:)


5 0
4 years ago
Read 2 more answers
tom took a trip of 1,020 miles. he traveled by train at 55 miles an hour and the same number of hours by plane at 285mph how man
Kamila [148]
D = vt

Distance traveled by train
d = 55t
Distance traveled by plane
d = 285t
Total distance
d = 1020

So, you do:
distance traveled by plane + distance traveled by train =  total distance
(55t) + (285t) = 1020

Solve for t
t = 3 hours

t is the time traveled by each so 3 hrs traveled by train and 3 hrs traveled by plane

Total time  = 3 + 3 = 6 hours







8 0
3 years ago
What is the value of A?​
AnnZ [28]

Answer:

the answer is 6 ___________________________

5 0
3 years ago
0,4 5,3 ,1 reflected over the x axis
Sedaia [141]

Answer:

5 I am pretty sure sorry If it wrong

7 0
3 years ago
How do you do these?
Assoli18 [71]
\bf 6\sqrt[4]{405}\quad now\to 
\begin{cases}
405\to 3\cdot 3\cdot 3\cdot 3\cdot 5\\
\qquad 3^4\cdot 5
\end{cases}
\\ \quad \\
6\sqrt[4]{3^4\cdot 5}\implies 6\cdot 3\sqrt[4]{5}\\
----------------------------\\
\bf 3\sqrt{49x^9y^{16}}\quad now\to 
\begin{cases}
49\to 7\cdot 7\to 7^2\\
x^9\to x^{2+2+2+2+1}\\
\qquad  x^2\cdot x^2\cdot x^2\cdot x^2\cdot x^1\\
\qquad (x^2)^4\cdot x\\
y^{16}\to y^{2+2+2+2+2+2+2+2}\\
\qquad y^2\cdot y^2\cdot y^2\cdot y^2\\
\qquad \cdot y^2\cdot y^2\cdot y^2\cdot y^2\\
\qquad (y^2)^8
\end{cases}
\\ \quad \\
3\sqrt{7^2(x^2)^4x(y^2)^8}\implies 3\sqrt{7^2(x^4)^2x(y^8)^2}
\\ \quad \\
3\cdot 7\cdot x^4\cdot y^8\sqrt{x}\implies 21x^4y^8\sqrt{x}
5 0
3 years ago
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