Answer:
In Labrador dogs, black coat is dominant to chocolate, normal vision is dominant to progressive retinal atrophy (PRA), and normal hip joint is dominant to hip dysplasia. All these genes assort independently. Two dogs that are heterozygous for alleles of all three genes are crossed. Using rules of probability (not a Punnett square), what is the chance that the first pup born to these dogs will be chocolate, have normal vision, and have normal hip joints?
BbVvHh x BbVvHh= BBVVHH, BbVvHh, BbVvHh, bbvvhh
Bb= black coat dominant
Vv= Normal vision dominant
Hh= Normal hip join dominant
probability of having a first born of these dogs will be chocolate, have normal vision and have normal hip joint is 0
Explanation:
As the punette square gives 3:1 phenotype having three black coat, normal vision and normal hip joint and one chocolate, progressive retina altropy and hip dysplasia
I believe rottening would be the answer. Rotting, dead plants and animal feaces make great fertilizers.
If I am correct it is The Third Trimester
I believe the correct answer would be <span>variation. The definition of variation in biology means,</span><span> any difference
between cells, individual organisms, or groups of organisms of any
species caused either by genetic differences or by the effect of environmental factors on the expression of the genetic potentials. So i think that organisms can also be classified as variation. Hope this helped. ♥ ☺
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