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user100 [1]
3 years ago
15

What does nine fifths equal

Mathematics
2 answers:
scoundrel [369]3 years ago
6 0
1 and 4/5.................. 
Dvinal [7]3 years ago
5 0
Nine fifths is equalized to 1.8
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Right triangle XYZ is shown. Y (2,6) (1, 2) 6 х 7 Z Rounded to the nearest hundredth of a unit, what is the length of the hypote
Dmitriy789 [7]

Answer:

8.12

Step-by-step explanation:

We obtain the distance between x and y

d = sqrt[(x2 - x1)² + (y2 - y1)²]

d = sqrt[(1 - 2)² + (2 - 6)²]

d = sqrt[1 + 16)

d = sqrt(17)

d² = 17

From Pythagoras rule;

Hypotenus = sqrt(Adjacent² + opposite²)

Hence,

Hypotenus = sqrt(17 + 7²)

Hypotenus = sqrt(17+ 49)

Hypotenus = sqrt(66)

Hypotenus = 8.124

Hypotenus = 8.12

7 0
3 years ago
Fewer young people are driving. In 1983, 87% of 19-year-olds had a driver’s license. Twenty-five years later (in 2008) that perc
Dima020 [189]

Answer:

a) ME=1.96\sqrt{\frac{0.87 (1-0.87)}{1200}}=0.019  

b) ME=1.96\sqrt{\frac{0.75 (1-0.75)}{1200}}=0.0245  

c) On this case it's not the same since the proportion estimated for 1983 it's different from the proportion estimated for 2008. So since the margin of error depends of \hat p the margin of error change for part a and b.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=\pm 1.96

If we replace the values into equation (a) for 1983 we got:

ME=1.96\sqrt{\frac{0.87 (1-0.87)}{1200}}=0.019  

Part b

Since is the same confidence level the z value it's the same.  

If we replace the values into equation (a) for 2008 we got:

ME=1.96\sqrt{\frac{0.75 (1-0.75)}{1200}}=0.0245  

Is the margin of error the same in parts (a) and (b)? Why or why not?

On this case it's not the same since the proportion estimated for 1983 it's different from the proportion estimated for 2008. So since the margin of error depends of \hat p the margin of error change for part a and b.

3 0
3 years ago
An empty truck and a fully loaded truck Are next to each other at a traffic light when the light turned green the lighter truck
Ksenya-84 [330]
<span>C) Newton's second law : Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.</span>
4 0
3 years ago
Geometry question answer "c" is incorrect.
Black_prince [1.1K]
I also believe B is the answer...i belive :)
5 0
3 years ago
Rewrite in simplest form<br> 1/8 divide by 3/4
nata0808 [166]
Hello there!

1/8 ÷ 3/4

= 1/8 * 4/3

= 1/24/4

=1/96

= 0.01

I hope this helps!
5 0
3 years ago
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