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MrMuchimi
2 years ago
6

I need help asp please!!

Mathematics
1 answer:
luda_lava [24]2 years ago
5 0
The answer is r have a good day
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The length of a rectangle is 12 in and the perimeter is 56 what us the width of the rectangle
Aleks [24]
Hi there!

We can find the perimeter of a rectangle by using the following formula:

perimeter = 2 × width + 2 × length

In the question, we are given the following data: the length of the rectangle is 12 in and the perimeter is 56. Let's substitute this into our formula!

56 = 2 × width + 2 × 12
Multiply first.

56 = 2 × width + 24
Now subtract 24 from both sides.

32 = 2 × width
And finally, to find the width of the rectangle, divide both sides of the equation by 2.

16 = width
(we can eventually switch sides in the equation).

width = 16
~ Hope this helps you!
3 0
3 years ago
1. Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 c
prisoha [69]

Answer:

See explanation

Step-by-step explanation:

Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 chose the aisle seat, then

P(\text{Window seat})=\dfrac{492}{806}=\dfrac{246}{403}\\ \\P(\text{Middle seat})=\dfrac{8}{806}=\dfrac{4}{403}\\ \\P(\text{Aisle seat})=\dfrac{306}{806}=\dfrac{153}{403}

a) One randomly selected person preferes aisle seat with probability

\dfrac{153}{403}

b) Two randomly selected people both prefer aisle seat (with replacement) is

\dfrac{306}{806}\cdot \dfrac{306}{806}=\dfrac{153}{403}\cdot \dfrac{153}{403}=\dfrac{23,409}{162,409}

c) Two randomly selected people both prefer aisle seat (without replacement) is

\dfrac{306}{806}\cdot \dfrac{305}{805}=\dfrac{153}{403}\cdot \dfrac{61}{161}=\dfrac{9,333}{64,883}

8 0
2 years ago
please help i will mark brainliest, no spam answers i will report.
vovikov84 [41]

9514 1404 393

Answer:

  (c)  (3, 3)

Step-by-step explanation:

Point E partitions both the x-distance and the y-distance in the ratio 2 : 1. That is, for either the x-coordinates or the y-coordinates, ...

  CE : ED = 2 : 1

Try the answers with the x-coordinates.

  CE : ED = (1 -(-1)) : (5 - 1) = 2 : 4 . . . . incorrect

  CE : ED = (-3 -(-1)) : (5 -(-3)) = -2 : 8 . . . . incorrect

  CE : ED = (3 -(-1)) : (5 -3) = 4 : 2 = 2 : 1 . . . . correct

  CE : ED = (-1 -(-1)) : (5 -(-1)) = 0 : 6 . . . . incorrect

The only viable choice is (3, 3).

_____

<em>Alternate solution</em>

For a partitioning of m : n, the desired point is ...

  E = (n×C +m×D)/(m+n)

For partitioning of 2 : 1, the desired point is ...

  E = (1×(-1, -3) + 2×(5, 6))/(2+1) = (-1+10, -3 +12)/3

  E = (3, 3)

3 0
2 years ago
How do you subtract integers?<br> like -81-(-34)
DedPeter [7]

Answer:

-47

Step-by-step explanation:

For this problem, we can use the rule "two negatives make a positive".

-81-(-34)

= -81 + 34

If you subtract 34 from 81, you find the opposite positive/negative answer.

81 - 34 = 47

Change all of the positive/negative signs:

-81 + 34 = -47

8 0
3 years ago
Ursula and Andre competed against each other in a swimming race. Ursula swam at a rate of 60 meters per minute and Andre swam at
Lubov Fominskaja [6]
Given that the two swimmers competed and Ursula's speed is 60 m/min while Andre's speed is 48 m/min. The distance that the Ursula will catch up with Andre will be:
distance=(relative speed)×(time)
relative speed=60-48=12 m/min
the two swimmers met at a distance of:
12×1
=12 meters

6 0
3 years ago
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