Step-by-step explanation:
a) 3x + 5y = 8
4x - 3y = 1
• using the elimination method:
3x + 5y = 8 (×4)
4x -3y = 1 (×3)
12x + 20y = 32
12x -9y = 3
subract 12x from both equation:
20y - - 9y= 32 -3
20y +9y = 29
29y= 29
y= 29/29
y= 1
- substituting y= 1 in :
4x - 3y= 1
4x - 3(1) = 1
4x -3 = 1
4x = 1 + 3
x = 4/4
x= 1
b) 6p+ 4q = 20
5p - 2q = 6
• using the elimination method:
6p + 4q = 20
5p - 2q = 6 (×2)
6p + 4q = 20
10p - 4q = 12
add 4q + -4q to eliminate q.
6p+ 10p = 20+12
16p = 32
p = 32/ 16
p = 2
- subtituting p = 2 in :
5p - 2q = 6
5(2) -2q =6
10 -2q = 6
-2q = 6 - 10
q = -4 / -2
q = 2
hope this helps you,
-s.
Answer:
6/50
Step-by-step explanation:
<span>It is possible for two points to have the same x-coordinate and the same y-coordinate. </span>
Answer:
1) 16
2a) 100 -a -2b
2bi) (100 -a -2b)/4
2bii) 11
Step-by-step explanation:
1. Put the numbers where the corresponding variables are and do the arithmetic.
(2(1) +3(-2))^2 = (2 -6)^2 = (-4)^2 = 16
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2. The pieces cut from the wire have the lengths a, b, b. The sum of those lengths is a+b+b = a+2b.
2a. The remaining length is what is left when the total of cut pieces is subtracted from the original amount:
100 -(a+2b) = 100 -a -2b
2bi. The perimeter of the square is the amount in part (2a). A square has 4 sides of the same length, so each side has a length that is 1/4 of the perimeter. The side length is ...
(100 -a -2b)/4 . . . . length of one side of the square
2bii. Fill in the given values for "a" and "b" and do the arithmetic.
(100 -24 -2(16))/4 = (76 -32)/4 = 44/4 = 11 . . . one side of the square