Is 5/12 or 8/10 larger?

Plz help me :) dropdowns

ollegr [7]

Answer:

1

Step-by-step explanation:

3 0

3 years ago

I need it ASAP! Tristan swam around a lake 8 times. The distance around the lake was 0.25 miles. He swam at an average of 60 min

yarga [219]

Total of 8 times
Distance is 0.25 miles

8 * 0.25 is 2 so a total distance of 2 miles

We know his avg swim rate to be 60 minutes per mile, meaning if he traveled 2 miles then we multiply it by 60 to get our total time taken.

60min/mile * 2 miles = 120 minutes total

So, step D is the same as what I've done to calculate the total time it will take Tristan to swim around the lake.

7 0

3 years ago

Mrs. Garcia is painting a portion of her wall as shown.

Alexandra [31]

Answer:

Step-by-step explanation:

3 0

3 years ago

24 inches per minute converts to how many miles per day

12345 [234]

Answer:

0.545455

Step-by-step explanation:

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cbegin%7Bbmatrix%7D%20%5Cbegin%7Barray%7D%20%7B%20l%20l%20%7D%20%7B%202%20%7D%20%

SVETLANKA909090 [29]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

In matrix multiplication, the number of columns in the 1st matrix is equal to the number of rows in the 2nd matrix.

$\left(\begin{matrix}2&3\\5&4\end{matrix}\right)\left(\begin{matrix}2&0&3\\-1&1&5\end{matrix}\right)$

Multiply each element of the 1st row of the 1st matrix by the corresponding element of the 1st column of the 2nd matrix. Then add these products to obtain the element in the 1st row, 1st column of the product matrix.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&&\\&&\end{matrix}\right)$

The remaining elements of the product matrix are found in the same way.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&3&2\times 3+3\times 5\\5\times 2+4\left(-1\right)&4&5\times 3+4\times 5\end{matrix}\right)$

Simplify each element by multiplying the individual terms.

$\left(\begin{matrix}4-3&3&6+15\\10-4&4&15+20\end{matrix}\right)$

Now, sum each element of the matrix.

$\large\boxed{\boxed{\left(\begin{matrix}1&3&21\\6&4&35\end{matrix}\right) }}$

7 0

3 years ago