I = / r where I = current and r = resistance
80 = k / 50 so
k = 400
so we have I = 400/r
when r = 40
I = 400/40 = 10 amps
Let A = the event that the first ball is odd number
and B = the event that the second ball is odd number
In the beginning, there are 25 balls which contain 13 balls of odd numbers. So the probability for the first selection (as to expect you would draw a ball of an odd number) is
P(A) = 13/25
After the selection, the rule does not allow replacement. So, there are 24 balls left containing now 12 balls of odd numbers. So the probability for the second selection (as to expect you would draw also a ball of odd number) is
P(B) = 12/24 = 1/2
Multiplying the two probabilities obtains
P(2 odd numbers) = 13/25 * 1/2 = 13/50
Answer:
2 strawberries
Step-by-step explanation:
Given that:
Number of strawberries :
Ona has 8
Barton has 4
For both Ona and Barton to have the same Nunber of strawberries :
(Ona + Barton) /2 = (8 + 4) / 2 = 12 /2 = 6
That means both Ona and Barton will have 6 strawberries each
Hence,
Barton who has 4 strawberries needs 2 more while Ona who has 8 will give out 2
Hence, Ona should give two strawberries to Barton.
Answer:
-231.55
Step-by-step explanation:
The answer is 0.88889, because:
Order of Operations-
1) Add 30 plus 6 to get 36
2) Subtract 32 from 36 to get 4
3) Divide 4 by 9 to get 0.4444444
4) Multiply 0.4444444 by 2 to get 0.888889
Good luck! <3
