Answer:
8 mice with black fur, 1 mouse with white fur
5 mice with black fur, 6 mice with white fur
6 mice with black fur, 2 mice with white fur
Explanation:
Let the allele for black color fur be represented by "B" and the allele for white color fur be represented by "b"
Also let the black color be dominant over white color fur.
Genotype for homozygous black and white mouse will be "BB" and "bb"
In case if the black fur mouse if heterozygous, then its genotype would be "Bb"
Now if a cross is carried out between black fur and a mouse with white fur, we get -
Bb * bb
Bb, Bb, bb, bb
So the correct answer is option
8 mice with black fur, 1 mouse with white fur
5 mice with black fur, 6 mice with white fur
6 mice with black fur, 2 mice with white fur