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ipn [44]
2 years ago
5

Plants can reduce global warming, because photosynthesis requires _______.

Biology
2 answers:
stealth61 [152]2 years ago
7 0

The answer to this question is that photosynthesis requires carbon dioxide. Photosynthesis is the process where plants converts the light from the sunlight into a chemical energy like oxygen and organic compounds. Plants also use photosynthesis in order for the plants to make food. 

Salsk061 [2.6K]2 years ago
3 0

Answer: Carbon Dioxide

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<em>Answer: In dehydration synthesis reactions, a water molecule is formed as a result of generating a covalent bond between two monomeric components in a larger polymer. In hydrolysis reactions, a water molecule is consumed as a result of breaking the covalent bond holding together two components of a polymer.</em>

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Hippies were young Americans who lived the counterculture lifestyle
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4. What type of cells are haploid?
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7 0
2 years ago
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Which of the following samples will have the greatest volume at STP?a. 22 g Neb. 22 g Hec. 22 g O2d. 22 g Cl2 e. All have the sa
sammy [17]

Answer:

22g of He

Explanation:

Volume of gas at STP is given as :

Volume occupied(dm³) = number of moles x 22.4dm³mol⁻¹

In order to solve this given problem, we would first find the number of moles from the different masses of atoms and molecules given.

Number of moles = \frac{mass }{Molar mass}

Now, let us obtain the molar mass of the given atoms and elements:

For Ne; molar mass is the atomic mass = 20gmol⁻¹

      He = 4gmol⁻¹

      O₂ = (16 x2)gmol⁻¹  = 32gmol⁻¹

      Cl₂ = (35.5x2)gmol⁻¹ = 71gmol⁻¹

Number of moles of Ne = \frac{22}{20} = 1.1mol

Volume occupied by Ne at STP = 1.1 x 22.4 = 24.64dm³

       

Number of moles of He = \frac{22}{4} = 5.5mol

Volume occupied by He at STP = 5.5 x 22.4 = 123.2dm³

Number of moles of O₂ = \frac{22}{32}  = 0.688mol

Volume occupied by O₂ at STP = 0.688 x 22.4 = 15.4mol

Number of moles of Cl₂ = \frac{22}{71} = 0.3099mol

Volume occupied by Cl₂ at STP = 0.3099 x 22.4 = 6.94dm³

5 0
2 years ago
If the dna content of a diploid cell in the g1 phase of the cell cycle is represented by x, then the dna content of the same cel
s2008m [1.1K]
Mitosis and meiosis are both cell division process except that the former is only done by somatic cells and the latter is done by gametes. In G1 phase or the growth phase of interphase, there is increase in cellular substance without DNA replication therefore DNA will be regarded as x. By the time when S or synthesis phase of interphase is finished, DNA replication is done therefore all phases that follow the S phase will have a DNA of 2x. In this case, the cell in metaphase of meiosis I has double the amount of DNA than the one in G1 phase because this cell already underwent the S phase. In meiosis, after the first division (meiosis I), there is reduction of genetic material into half (hence called reduction division) producing haploid cells. So a cell in the metaphase of meiosis II will have DNA half of that in metaphase of meiosis I thereby regarded as x.
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3 years ago
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