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3 years ago

I don’t get it ?? could someone work through it so I can understand how you get to the answer, thanks

Mathematics

2 answers:

ale4655 [162]3 years ago

6 0

the answer would be 60 if im corrected

VikaD [51]3 years ago

5 0

if sum of the angle measures total 360, you see in the diagram that adding all of thme up should get you 360

2a + a + 2a + a = 360

6a = 360

a = 60

the angles are 60, 60, 120, 120

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Can you please answer ASAP I need the answer

Alika [10]

Answer:

I think x=8

Step-by-step explanation:

5(x+7)+15=90

90 because it's a 90 degree angle

5x+35+15=90

5x+50=90

5x=40

x=8

7 0

3 years ago

Use the information to answer the question.

ArbitrLikvidat [17]

Answer:

10 hats

Step-by-step explanation:

Original price

$24.98

Sale price

$24.98*1.5 = $37.47 for two hats

Total cost

$187.35

Hats sold:

187.35/37.47 *2 = 10 hats

6 0

4 years ago

A delivery truck is transporting boxes of two sizes: large and small. The combined weight of a large box and a small box is 80 p

avanturin [10]

Answer:

small = 35 pounds

large = 45 pounds

Step-by-step explanation:

Let x = large boxes

y = small boxes

two equations can be derived from the question

x + y = 80 equation 1

60x + 65y = 4975 equation 2

multiply equation 1 by 60

60x +60y = 4800 equation 3

subtract equation 2 from 3

5y = 175

y = 35

substitute for y in equation 1

x + 35 = 80

x = 80 - 35

x = 45

6 0

3 years ago

PLEASE HELP NO WRONG ANSWERS

Evgesh-ka [11]

Answer:

I believe it's C

Step-by-step explanation:

8 0

3 years ago

The distribution of weights for newborn babies is approximately normally distributed with a mean of 7.4 pounds and a standard de

blsea [12.9K]

Answer:

1. 15.87%

2. 6 pounds and 8.8 pounds.

3. 2.28%

4. 50% of newborn babies weigh more than 7.4 pounds.

5. 84%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 7.4 pounds

Standard Deviation, σ = 0.7 pounds

We are given that the distribution of weights for newborn babies is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

1.Percent of newborn babies weigh more than 8.1 pounds

P(x > 8.1)

$P( x > 8.1) = P( z > \displaystyle\frac{8.1 - 7.4}{0.7}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 8.1) = 1 - 0.8413 = 0.1587 = 15.87\%$

15.87% of newborn babies weigh more than 8.1 pounds.

2.The middle 95% of newborn babies weight

Empirical Formula:

Almost all the data lies within three standard deviation from the mean for a normally distributed data.
About 68% of data lies within one standard deviation from the mean.
About 95% of data lies within two standard deviations of the mean.
About 99.7% of data lies within three standard deviation of the mean.

Thus, from empirical formula 95% of newborn babies will lie between

$\mu-2\sigma= 7.4-2(0.7) = 6\\\mu+2\sigma= 7.4+2(0.7)=8.8$

95% of newborn babies will lie between 6 pounds and 8.8 pounds.

3. Percent of newborn babies weigh less than 6 pounds

P(x < 6)

$P( x < 6) = P( z > \displaystyle\frac{6 - 7.4}{0.7}) = P(z < -2)$

Calculation the value from standard normal z table, we have,

$P(x < 6) =0.0228 = 2.28\%$

2.28% of newborn babies weigh less than 6 pounds.

4. 50% of newborn babies weigh more than pounds.

The normal distribution is symmetrical about mean. That is the mean value divide the data in exactly two parts.

Thus, approximately 50% of newborn babies weigh more than 7.4 pounds.

5. Percent of newborn babies weigh between 6.7 and 9.5 pounds

$P(6.7 \leq x \leq 9.5)\\\\ = P(\displaystyle\frac{6.7 - 7.4}{0.7} \leq z \leq \displaystyle\frac{9.5-7.4}{0.7})\\\\ = P(-1 \leq z \leq 3)\\\\= P(z \leq 3) - P(z < -1)\\= 0.9987 -0.1587= 0.84 = 84\%$

84% of newborn babies weigh between 6.7 and 9.5 pounds.

7 0

4 years ago