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3 years ago

9

Select one card from two cards, one colored red, one colored blue. replace the card and repeat the experiment. what is the proba

bility of selecting a blue card each time?

1 answer:

elena55 [62]3 years ago

4 0

The probability of picking the blue card is 1/2 each time.

The probability of picking it BOTH times is

(1/2)•(1/2) = 1/4. (25%)

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Adrian's CD player can hold six disks at a time and shuffles all of the albums and their songs. If he has thirteen CD's, how man

EastWind [94]

To answer this problem, the utilization of the provided formula is of utmost importance.

The formula to be used would be for the combination with no repetition since it is what is asked and possibly happens when involving the products mentioned in the problem. The formula would be

n! where in
------------- n = number of things to choose from
(n - r)! r! r = number of things needed to form

the symbol ! is called a factorial function which replaces the sequence of multiplying a number in a descending order.

lets substitute and solve

13!
--------------
(13 - 6)! 6!

13!
-------------
(7!) 6!

6,227,020,800
-------------------
5,040 x 720

6,227,020,800
-------------------
3,628,800

1,716

The answer would be 1,716.

6 0

3 years ago

F(x)=3x-4 and g(x) = x2 find the value of f(3)-g(2) <br><br> show all work

zheka24 [161]

Answer: 1

f(x) = 3x - 4 => f(3) = 3.3 - 4 = 9 - 4 = 5

g(x) = x² => g(2) = 2² = 4

=> f(3) - g(2) = 5 - 4 = 1

Step-by-step explanation:

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2 years ago

Can I get help please

WITCHER [35]

Answer:

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Step-by-step explanation:

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2 years ago

I think I got this wrong so can someone please help me and explain it to me

Ber [7]

Answer:

the answer is c

Step-by-step explanation:

Becuase he is given 100 dollars and he uses 20 dollars a day, so you put x with 20 to calculate how many days that he can spend $20 on

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2 years ago

Read 2 more answers

Write the equation of a possible rational

kondor19780726 [428]

Answer:

The graph has a removable discontinuity at x=-2.5 and asymptoe at x=2, and passes through (6,-3)

Step-by-step explanation:

A rational equation is a equation where

$\frac{p(x)}{q(x)}$

where both are polynomials and q(x) can't equal zero.

1. Discovering asymptotes. We need a asymptote at x=2 so we need a binomial factor of

$(x - 2)$

in our denomiator.

So right now we have

$\frac{p(x)}{(x - 2)}$

2. Removable discontinues. This occurs when we have have the same binomial factor in both the numerator and denomiator.

We can model -2.5 as

$(2x + 5)$

So we have as of right now.

$\frac{(2x + 5)}{(x - 2)(2x + 5)}$

Now let see if this passes throught point (6,-3).

$\frac{(2x + 5)}{(x - 2)(2x + 5)} = y$

$\frac{(17)}{68} = \frac{1}{4}$

So this doesn't pass through -3 so we need another term in the numerator that will make 6,-3 apart of this graph.

If we have a variable r, in the numerator that will make this applicable, we would get

$\frac{(2x + 5)r}{(2x + 5)(x - 2)} = - 3$

Plug in 6 for the x values.

$\frac{17r}{4(17)} = - 3$

$\frac{r}{4} = - 3$

$r = - 12$

So our rational equation will be

$\frac{ - 12(2x + 5)}{(2x + 5)(x - 2)}$

or

$\frac{ - 24x - 60}{2 {x}^{2} + x - 10}$

We can prove this by graphing

5 0

2 years ago