Answer:
(a) i and ii: 2b-2 = b+b-2
(b) i and iii: c+d = d+c
(c) ii and iii: a + 2b - 1 = a+b-1+b
(d) i and iii: x+(y-z) = x-(z-y)
(e) ii and iii: (a-1)² = (1-a)²
(f) i and ii: 3a-b-1-1 = 3a+b-2-2b
Step-by-step explanation:
let me know if you require detailed explanation for any of them.
<u>The question was written by the student in a comment because the image contains no question at all.</u>
- <u>Kathy sells candles for $3 and flowers for $5. She plans to sell at least 200 items and likes to earn a minimum of $2500.
</u>
Answer:
Step-by-step explanation:
<u>System of equations</u>
Kathy sells candles for $3 and flowers for $5. Let's set the following variables:
x = number of candles Kathy sells
y = number of flowers Kathy sells
She plans to sell 200 items, thus:
x + y = 200
She also likes to earn $2,500. The equation for this condition is:
3x + 5y = 2500
The system of equations is
So we first minus 6 both sides
7x^2-14x=-6
then we have
A(x^2-2x)=-6
what is A?
hmm (this should be painfully obvous, but if not, here are steps)
7x^2-14x=-6
A(x^2-2x)=-6
7x^2-14x=-6=A(x^2-2x)
7x^2-14x=A(x^2-2x)
undistribute 7
7(x^2-2x)=A(x^2-2x)
divide both sides by (x^2-2x)
7=A
A=7
Answer:
(x + 12) / 4
Explanation:
This was the way I was taught, hopefully it helps you.
y = 4x - 12
x = 4y - 12
x + 12 = 4y
(x + 12) / 4 = y
Answer:
(1, 4) and (1,3), because they have the same x-value
Step-by-step explanation:
For a relation to be regarded as a function, there should be no two y-values assigned to an x-value. However, two different x-values can have the same y-values.
In the relation given in the equation, the ordered pairs (1,4) and (1,3), prevent the relation from being a function because, two y-values were assigned to the same x-value. x = 1, is having y = 4, and 3 respectively.
Therefore, the relation is not a function anymore if both ordered pairs are included.
<em>The ordered pairs which make the relation not to be a function are: "(1, 4) and (1,3), because they have the same x-value".</em>
