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bulgar [2K]
2 years ago
14

Help with this one pls!! Show steps if u can Thanks :)

Mathematics
1 answer:
goldenfox [79]2 years ago
8 0

Answer:

74

Step-by-step explanation:

93.795 ÷ 126 \frac{3}{4} %

= 74

and

74 x 126 \frac{3}{4} %

= 93.795

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What is the correct answer?
Svetlanka [38]

Answer:

Terms must have the same variable (letter) and the same exponent (little number)

(7x² +3y+ 5) +(9x²+11y- 2)

Opening bracket

7x²+3y+5+9x²+11y-2

keeping like terms together

7x²+9x²+3y+11y+5-2

Since terms having same variable and exponent can be subtracted, added,divided and multiplied

So

Solving like terms we get

<u>16x²+14y+3</u> which is a correct answer.

4 0
2 years ago
How do you write 982% as a fraction, mixed number, or whole number in simplest form?
koban [17]
I think one of the answers would be 9.82
8 0
3 years ago
Read 2 more answers
Make 'h' as the subject. Remember to rationalize the denominator while solving.
Sliva [168]

Hello there BeGuiLE !

To solve your question,  we must first bring 'h' to one side of the equation.  Let's bring all the terms with the variable 'h' to the left side of the equation. So,
\large{\sf\sqrt{ 3  }  h =  1.6+h}
→ \large{\sf\sqrt{3}h-h=1.6 }

Now, let's combine the 2 terms containing the variable 'h'.
\large{\sf\sqrt{3}h-h=1.6 }
→ \large{\sf\left(\sqrt{3}-1\right)h=1.6 }

Now, we need to leave the variable 'h' alone in the left side of the equation & bring (√3 + 1) to the other side of the equation. This is done in order to make 'h' as the subject of the equation. So, we'll get it as,
\large{\sf\left(\sqrt{3}-1\right)h=1.6 }
→ \large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }

Now, let's rationalize it. Rationalizing is a process where we move the root from the denominator of a fraction to the numerator for easier calculation. So,
\large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }
→ \large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{(\sqrt{3}-1 )(\sqrt{3}+1}) }
Now, use the algebraic identity, (a + b)(a - b) = a² - b²
→ \large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{3-1} }
→ \large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{2} }
→ \boxed{\large{\sf\:h=0.8(\sqrt{3}+1)}}

Now, we've made 'h' as the subject of the equation. If you want to solve it more, then,
\large{\sf\:h=0.8(\sqrt{3}+1)}
Take √3 as 1.73 (approx. value up to 2 decimal places)
→ \large{\sf\:h=0.8(1.73+1)}
→ \large{\sf\:h=0.8(2.73)}
→ \boxed{\boxed{\huge{\bf{\:h=2.184 \: (approx.)}}}}

I hope this will help you.

Please refer to the attached image if the explanation shows some error.

_______

Check out more links which will help you understand the topic better :

■ brainly.com/question/21406377

■ brainly.com/question/696184

_______
\mathfrak{Lucazz}


4 0
2 years ago
Read 2 more answers
In 24 days Elmo will celebrate his birthday he will be 12 years old how many weeks until his birthday????
koban [17]
3 weeks and 3 days is the answer. This is bc 21/7 is 3. And the left over is 3
7 0
3 years ago
Read 2 more answers
16.404÷6=<br><br> help me<br>please and thank you​
Marina CMI [18]
Hey the answer is 2.734
6 0
3 years ago
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