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2 years ago

Help with this one pls!! Show steps if u can Thanks :)

Mathematics

1 answer:

goldenfox [79]2 years ago

8 0

Answer:

Step-by-step explanation:

93.795 ÷ 126 $\frac{3}{4}$ %

= 74

and

74 x 126 $\frac{3}{4}$ %

= 93.795

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Adrian is drawing a map to show the directions from his house to his grandmother's house. He uses a scale of 1 1/2

Nadya [2.5K]

It’s going to be 4 1/2 inches.
36/12=3
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3 years ago

How do I do this fraction with Distributive Property???

Olenka [21]

Answer:

$3a - 1$

Explanation:

$\frac{9a - 3}{3}$

Factor out 3

$\frac{3(3a - 1)}{3}$

Cancel out the common factor 3

$3a - 1$

5 0

2 years ago

Can someone pls help with this and please explain how u got the answer or you wont receive credit. And this id due in 8 minutes

aalyn [17]

Answer:

Answer to A: Each pound of coffee costs $6.32 dollars. Answer to B: He could buy 0.16 pounds of coffee for $1 dollar.

Step-by-step explanation:

For A, we use division. He payed $18.96 dollars for 3 pounds for coffee.

18.96 / 3 = 6.32.

Each pound of coffee costs $6.32 dollars.

For B, we use division Again.

The amount of pounds he could buy for $1 dollar is 0.16 pounds of coffee.

Hope this helps!

If you like it, please mark me as brainiest!

8 0

2 years ago

Read 2 more answers

PLEASE ANSWER THIS ASAP

Arisa [49]

Answer:

The equation of line passes through $(4,-1)$ and perpendicular to the graph $y=\frac{7}{2}x-\frac{3}{2}$ is $y=\frac{-2x}{7}+\frac{1}{7}$

Step-by-step explanation:

Given point is $(4,-1)$ and equation of line is $y=\frac{7}{2}x-\frac{3}{2}$

Let the slope of line that passes through point $(4,-1)$ is $m_1$

And slope of line $y=\frac{7}{2}x-\frac{3}{2}$ is $m_2=\frac{7}{2}$ . As it is in the form of $y=mx+c$

We know the relation between slope of perpendicular line are given by

$m_1\times m_2=-1\\And\ m_1=\frac{-1}{m_2}$

So, the slope $m_1=\frac{-1}{\frac{7}{2}}=\frac{-2}{7}$

Now, we can write the equation of line having point $(4,-1)$ and slope $\frac{-2}{7}$

$(y-y_1)=m(x-x_1)\\\\(y-(-1))=\frac{-2}{7}(x-4)\\\\y+1=\frac{-2x}{7}-(\frac{2\times -4}{7})\\ \\y+1=\frac{-2x}{7}+\frac{8}{7}\\\\y=\frac{-2x}{7}+\frac{8}{7}-1\\\\y=\frac{-2x}{7}+\frac{8-7}{7}\\\\y=\frac{-2x}{7}+\frac{1}{7}$

So, the equation of line passes through $(4,-1)$ and perpendicular to the graph $y=\frac{7}{2}x-\frac{3}{2}$ is $y=\frac{-2x}{7}+\frac{1}{7}$

3 0

3 years ago

How much is 2% of 3.50

Vesnalui [34]

Answer:

0.07

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers