Question

Area of a rectangle is 81 m^2. Express the perimeter of the rectangle as a function of the length (L) of one of its sides

Answer 1

Answer:

$P = 2\bigg(\dfrac{l^2 + 81}{l}\bigg)~m$

Step-by-step explanation:

We are given the following in the question:

Area of rectangle = 81 square meter.

Let l be the length of the rectangle and b be the breadth of rectangle.

Then, we can write,

$\text{Area of rectangle} = \text{Length}\times \text{breadth}\\A = l\times b\\81 = l\times b\\\\b = \dfrac{81}{l}~m$

Perimeter of rectangle =

$2(\text{Lenght + Breadth})$

Putting values, we get,

$P = 2(l + b)\\P = 2(l + \dfrac{81}{l})\\\\P = 2\bigg(\dfrac{l^2 + 81}{l}\bigg)~m$