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Sloan [31]
3 years ago
15

Is point (2,1) on the the line represented by the equation x+2y=5

Mathematics
2 answers:
MrMuchimi3 years ago
7 0
(x,y)
(2,1)
that means x=2 and y=1 is true, or is it?
just subsitute 2 for x and 1 for y and see if you get a true statement

2+2(1)=5
2+2=5
4=5
false
it is not on the line
Sphinxa [80]3 years ago
6 0
To check if this point lies on the line, plug in a 2 for x and a y for 1 and solve

x+2y=5
2+2(1)=5
4=5

Since this statement isn't true, then the point doesn't lie on the line

Hope this helps

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What is the simplified form of x+6 over x+4 + x-3 over 3
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1 Cancel <span>33</span>
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2 Collect like terms
<span>(x+x)+\frac{6}{x}+(4-1)<span>(x+x)+<span><span>​x</span>​<span>​6</span><span>​​</span></span>+(4−1)</span></span>
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7 0
3 years ago
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Answer:

y =  \frac{2}{3} x + 12

Step-by-step explanation:

y =  -  \frac{3}{2} x - 1

The gradient of a line is the coefficient of x when the equation of the line is written in the form of y=mx+c.

Thus, gradient of given line=-  \frac{3}{2}.

The product of the gradients of perpendicular lines is -1.

(Gradient of line)(-3/2)= -1

Gradient of line

- 1 \div ( -  \frac{3}{2} ) \\  =  - 1( -  \frac{2}{3} )  \\  =  \frac{2}{3}

Substitute m=\frac{2}{3} into y=mx+c:

y =  \frac{2}{3} x + c

To find the value of c, substitute a pair of coordinates.

When x= -6, y= 8,

8 =  \frac{2}{3} ( - 6) + c \\  \\ 8 =  - 4 + c \\ c = 8 + 4 \\ c = 12

Thus, the equation of the line is y =  \frac{2}{3} x + 12.

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3 years ago
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Answer:

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Step-by-step explanation:

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Answer

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so, prob = remaining males/remaining students=16/43

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