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2 years ago

6 more than 5 times a number y

Mathematics

2 answers:

natta225 [31]2 years ago

7 0

6+5y is the equation

Leya [2.2K]2 years ago

6 0

6 more than 5 times a number y = 6+5y

6 more than = 6 +

5 times a number y = 5 * y or 5y

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Help please ASAP please I’ll mark you as brainlister

storchak [24]

Answer:

a = 4

Step-by-step explanation:

$\sin(theta) = \frac{opposite}{hypotenuse}$

$\cos(theta) = \frac{adjacent}{hypotenuse}$

$\tan(theta) = \frac{opposite}{adjacent}$

hypotenuse = a

opposite = 2√3

adjacent = b

theta = 60°

the best formula to use is the first formula cause we have all the values to substitute in it in order to find the value of a

$\sin(60) = \frac{2 \sqrt{3} }{a}$

$\frac{2 \sqrt{3} }{ \sin(60) } = a$

$4 = a$

$a = 4$

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3 years ago

A typical container of orange juice concentrate holds 12 fluids ounces (fl oz). The standard recipe is "Mix one can of concentra

dangina [55]

$The\ standard\ recipe\ is:\\\ 12\ fl\ oz\of\ orange\ juice\ concentrate\\ and\ 3\cdot 12=36\ fl\ oz\ of cold\ water\\so\ is\ 12+36=48\ fl\ oz\ of\ mix\\\\128:48=2 \frac{2}{3} \\\\Ans.\ Olivia\ need\ \ 2 \frac{2}{3}\ cans\ of\ orange\ juice\ concentrate.$

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3 years ago

Help me please !!!!!!!!!

ANTONII [103]

The answer in b next time make sure the picture is clear

3 0

3 years ago

If a1 = 9 and and an-1 - 5 then find the value of a6.

SCORPION-xisa [38]

Answer:

a1 = 6 and an = an-1 - 5

a2 = a2-1 - 5 = a1 - 5 = 1

a3 = a3-1 - 5 = a2 - 5 = -4, etc

Step-by-step explanation:

8 0

2 years ago

For the month of November in a certain city, 88% of the days are cloudy. Also in the month of November in the same city, 54%

Gnoma [55]

Answer:

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.

Step-by-step explanation:

We have these following probabilities:

An 88% probability that the day is cloudy.

An 54% probability that the day is both foggy and cloudy.

What is the probability that a randomly selected day in November will be foggy if it is cloudy?

This is the percentage of days that are cloudy and foggy divided by those that are cloudy. So:

$P = \frac{0.54}{0.88} = 0.6136$

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.

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3 years ago