Hey there,
6x + 5 (x-2)
6x + 5x - 10
11x - 10
3x - 5 - x + 9
3x - x - 5 + 9
2x + 4
3a + 5 - 8a + 1
3 (-1) + 5 - 8(-1) + 1
-3 + 5 + 8 + 1
11
Hope this helps :))
<em>~Top♥</em>
Given :
An equation, 2cos ß sin ß = cos ß .
To Find :
The value for above equation in (0, 2π ] .
Solution :
Now, 2cos ß sin ß = cos ß
2 sin ß = 1
sin ß = 1/2
We know, sin ß = sin (π/6) or sin ß = sin (5π/6) in ( 0, 2π ] .
Therefore,
![\beta = \dfrac{\pi}{6}\ or\ \beta = \dfrac{5\pi}{6}](https://tex.z-dn.net/?f=%5Cbeta%20%3D%20%5Cdfrac%7B%5Cpi%7D%7B6%7D%5C%20or%5C%20%5Cbeta%20%3D%20%5Cdfrac%7B5%5Cpi%7D%7B6%7D)
Hence, this is the required solution.