Answer:
See Below.
Step-by-step explanation:
We are given that ΔAPB and ΔAQC are equilateral triangles.
And we want to prove that PC = BQ.
Since ΔAPB and ΔAQC are equilateral triangles, this means that:

Likewise:

Since they all measure 60°.
Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

Likewise:

Since ∠QAC ≅ ∠PAB:

And by substitution:

Thus:

Then by SAS Congruence:

And by CPCTC:

Answer:
IN 7 HOURS
Step-by-step explanation:
YOU DO 15*7+10
Step-by-step explanation:
Parallel lines have the same slope so they can therefore never touch. Just change the y-int. (Any number as long as it's not the same as the previous)
I.E.:
y = -3x - 12
Answer:
3t +15
Step-by-step explanation: first multiply the 3 to the T but you can't so you leave it 3t then 3 x 5 = 15 your sum is 3t +15
Answer: 37.5
Step-by-step explanation: just multiply! hope this helps!