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SOVA2 [1]
3 years ago
11

Determine the value of x in the figure. answers: A) x = 90 B) x = 40 C) x = 45 D) x = 135

Mathematics
1 answer:
guapka [62]3 years ago
5 0

Answer:

Please mark be brainliest and I hoped this helped!

x = 45°

Step-by-step explanation:

Since this is an isosceles triangle, that means that x, and the angle opposite from x, are the same. We take 135° and subtract that from 180°. That gives us 45°. Since the angle opposing x is 45°, then x is 45° as well.

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The percent decrease of an item that dropped in price from $50 to $43 is _____.
Stels [109]
Hopefully I’m correct but I think it is 7% because 50 -43 equals 7%
4 0
3 years ago
The table and the graph below each show a different relationship between the same two variables, x and y:
Angelina_Jolie [31]

Answer:

The answer is A.

Step-by-step explanation:

thats what i think

7 0
3 years ago
Find f(3) if f(x) = -2x + 14.<br><br><br> PLS HELP
Pachacha [2.7K]

Answer:

8

Step-by-step explanation:

Substitute 3 for x

-2x + 14

-2(3) + 14

-6 + 14 = 8

4 0
2 years ago
Read 2 more answers
A swim team must be chosen from 12 candidates. What is the greatest number of different 3-person teams that can be chosen?
grin007 [14]
<h3>Answer: 220 combinations</h3>

==========================================

Explanation:

We have 12*11*10 = 1320 permutations possible. This is where order matters. However, order does not matter with swim teams as there are no positions or ranks. All that matters is the group overall (rather than any individual in the group).

Consider the set {A,B,C}. We have 3*2*1 = 6 ways to arrange this set of letters. When considering a permutation, there are 6 permutations but only 1 combination since order doesnt matter and ABC is the same as BAC. Therefore, we divide 1320 over 6 to get the final answer of 1320/6 = 220.

---------

You can use the combination formula with n = 12 and r = 3. Doing so will give the following:

_n C _r = \frac{n!}{r!*(n-r)!}\\\\_{12} C _3 = \frac{12!}{3!*(12-3)!}\\\\_{12} C _3 = \frac{12!}{3!*9!}\\\\_{12} C _3 = \frac{12*11*10*9!}{3!*9!}\\\\_{12} C _3 = \frac{12*11*10}{3!}\\\\_{12} C _3 = \frac{12*11*10}{3*2*1}\\\\_{12} C _3 = \frac{1320}{6}\\\\_{12} C _3 = 220\\\\

As you can see, we get the same result and note how 1320/6 is also present as well.

8 0
3 years ago
Read 2 more answers
Graphs of Function,
andrew-mc [135]

Answer:

A function is increasing when the gradient is positive

A function is decreasing when the gradient is negative

<u>Question 7</u>

If you draw a tangent to the curve in the interval x < -2 then the tangent will have a positive gradient, and so the function is increasing in this interval.

If you draw a tangent to the curve in the interval x > -2 then the tangent will have a negative gradient, and so the function is decreasing in this interval.

If you draw a tangent to the curve at the vertex of the parabola, it will be a horizontal line, and so the gradient at x = -2 will be zero.

The function is increasing when x < -2

(- \infty,-2)

The function is decreasing when x > -2

(-2, \infty)

<u>Additional information</u>

We can actually determine the intervals where the function is increasing and decreasing by differentiating the function.

The equation of this graph is:

f(x)=-2x^2-8x-8

\implies f'(x)=-4x-8

The function is increasing when f'(x) > 0

\implies -4x-8 > 0

\implies -4x > 8

\implies x < -2

The function is decreasing when f'(x) < 0

\implies -4x-8 < 0

\implies -4x < 8

\implies x > -2

This concurs with the observations made from the graph.

<u>Question 8</u>

This is a straight line graph. The gradient is negative, so:

The function is decreasing for all real values of x

(- \infty,+ \infty)

But if they want the interval for the grid only, it would be -4 ≤ x ≤ 1

[-4,1]

<u>Question 9</u>

If you draw a tangent to the curve in the interval x < -1 then the tangent will have a negative gradient, and so the function is decreasing in this interval.

If you draw a tangent to the curve in the interval x > -1 then the tangent will have a positive gradient, and so the function is increasing in this interval.

If you draw a tangent to the curve at the vertex of the parabola, it will be a horizontal line, and so the gradient at x = -1 will be zero.

The function is decreasing when x < -1

(- \infty,-1)

The function is increasing when x > -1

(-1, \infty)

5 0
1 year ago
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