Ax + 3 = 7 - bx .....add bx to both sides
ax + bx + 3 = 7 ...subtract 3 from each side
ax + bx = 7 - 3
ax + bx = 4 ....factor out x
x(a + b) = 4 ...divide both sides by (a + b)
x = 4 / (a + b) <==
Answer:
Step-by-step explanation:
Once
You don't need to factor.
Answer:
Its the second one x=5
Step-by-step explanation:
I took the test.
Answer:
-2 and 18
Step-by-step explanation:
a + b = 16
ab = -36
a = (16-b)
b(16-b) = -36
16b - b² = -36
-b² + 16b + 36 = 0
b² - 16b - 36 = 0
(b+18)(b-2) = 0
The maximum value it can be would be 100%. The only times that it could be this high is when there is only a class on the frequency distribution table. Another way, is that there is only one column variable on the table (& or if there is only one row.) Any other time is will be less, but the maximum stays 100%.