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Anna35 [415]
3 years ago
9

What is the GCF of 18 and 36

Mathematics
2 answers:
Mkey [24]3 years ago
8 0
The greatest common factor would be 18 because 18 is the highest number than can go into 18 and 36 . Answer is 18
Marina86 [1]3 years ago
4 0
The greatest common factor is 8
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John wishes to pay off his car loan of $4,626 in 18 months. How much will his monthly payment be assuming he pays the same amoun
nydimaria [60]

Answer: $257 per month

Explanation:

Pay = monthly payment

Set the total cost equal to number of months times payment per month (which you would leave as a variable because that’s what you’re solving for).

4,626 = 18P

Divide both sides by 18 because you’re trying to isolate the P.

4,626 = 18P —-> 257 = Pr

This leaves you with an evenly split number of 257.

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
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Find sin theta if cot theta =-4 and cos theta &lt; 0
asambeis [7]
Imagine the unit circle. The cot(theta) is a line from (0,1) to (-4,1). Imagine it is part of a triangle with the origin (draw it!).

Then the hypotenuse length is √(1+4²) = √17.

The sine rule says that sin(90)/√17 must equal sin(theta)/4, and sin(90)=1, so

sin(\theta) = \frac4{\sqrt{17}}
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Many newspapers carmy a certain purzile in which the reader must unsoramble leers to form words how many warys cam the letters o
Kruka [31]

The correct unscrambling of whyrot is worthy.

<h3>What is unscrambling?</h3>
  • A word unscrambler is essentially a gadget that you feed all the letters into and it rearranges them to reveal all potential word combinations.
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  • A player may opt not to use the word generator and instead come up with their own list of terms. Having said that, they might want to utilize it afterward to assess their performance and review the entire list of terms they could have used.

To learn more about unscrambling with the given link

brainly.com/question/21327199

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3 0
2 years ago
he life of light bulbs is distributed normally. The variance of the lifetime is 625 and the mean lifetime of a bulb is 540 hours
almond37 [142]

Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 540, \sigma = \sqrt{625} = 25

The probability of a bulb lasting for at most 569 hours is the <u>p-value of Z when X = 569</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{569 - 540}{25}

Z = 1.16

Z = 1.16 has a p-value of 0.877.

0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

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2 years ago
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