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ZanzabumX [31]
3 years ago
12

Hi Plz help me with this question

Mathematics
2 answers:
sveticcg [70]3 years ago
7 0
Srry but I can’t figure this one out
Semmy [17]3 years ago
3 0
Answer: 3:54

Explanation: because if one foot is a proportional relationship to 18, then multiply both by 3 to get your answer.
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Plzzzz help mehh its scientific notation and im putting alot o point for it
s344n2d4d5 [400]
(7.2\cdot10^7)^2=7.2^2\cdot(10^7)^2=51.84\cdot10^{14}=\boxed{5.184\cdot10^{15}}=\\
\boxed{5,184,000,000,000,000}
5 0
3 years ago
This is a Khan Academy question from Trig
Paha777 [63]

Answer:

Option A

Step-by-step explanation:

By definition, tan∅=opposite/adjacent, so A would be your other option. HI represents the length of the side opposite to ∠H while GI represents the length of the side adjacent to ∠H.

Hope that clears things up!

4 0
3 years ago
What is the value of x in the equation<br> -3/4 x/24 .​
noname [10]

Answer: 18

Step-by-step explanation: PLEASE GIVE BRAINLIEST IT HELPS ALOT

8 0
3 years ago
If a and b are both positive, two-digit integers, is a + b a multiple of 11? The tens digit of a is equal to the units digit of
Serhud [2]

Answer:

Yes!

Step-by-step explanation:

Let x be the tens place and y be the units place. x and y need to be odd because in other case a or b will not be odd. For example, if x=1 and y=2 a will be 21 but b will be 12 that is not odd.

Now, a+b = xy+yx. Note that xy is not x*y, is just the digits concatenated.Then, there are two cases:

If x+y<10 then xy+yx = (x+y)(x+y) (again, that is not a multiplication is x+y concatenated with x+y) and that is 11*(x+y) a multiple of 11.

If x+y≥10 then xy+yx = (x+y+1)(x+y-10) because x+y<20.

Now we are going to see that last result without the concatenation, as a sum, that is

(x+y+1)*10 + x+y-10 = 10x+10y+10+x+y-10 = 11x+11y = 11(x+y). This result is clearly a multiple of 11.

In conclusion, in all cases the result of a+b is a multiple of 11.

6 0
3 years ago
Please Help ............
ASHA 777 [7]
It would be 40 degrees
8 0
3 years ago
Read 2 more answers
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