You need another equation to be able to solve this
Answer:
x= 16
y= -13
Step-by-step explanation:
x+y=3
x-3y=-29
Eliminate x and subtract the equations
2y=-26
y= -13
Plug in y for first or second equation
x=16
Answer:
From left to right: 1, 6, and 7
Step-by-step explanation:
If i did my math right it would be 13.
Answer:
the two positive consecutive integers are 4 and 6.
Step-by-step explanation:
Let the smaller integer be s; then s^2 = (s + 2) + 10.
Simplifying, s^2 - s - 2 - 10 = 0, or
s^2 - s - 12 = 0.
Solve this by factoring: (s - 4)(s + 3) = 0.
Then s = 4 and s = -3.
If the first even integer is 4, the next is 6. We omit s = -3 because it's not even.
The smaller integer is 4. Does this satisfy the equation s^2 = (s + 2) + 10?
4^2 = (4 + 2) + 10 True or False?
16 = 6 + 10 = 16.
True.
So the two positive consecutive integers are 4 and 6.
