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arsen [322]
4 years ago
9

Using the numbers 8, 6, 4, and 2 write an expression that equals 7.

Mathematics
2 answers:
nalin [4]4 years ago
5 0

Using all numbers:

1. (84:2):6=7; {here 84:2=42, 42:6=7}

2. 8-(6-4):2=7; {here 6-4=2, 2:2=1, 8-1=7}

3. (8:2):4+6=7; {here 8:2=4, 4:4=1, 1+6=7}

4. (8:4):2+6; {here 8:4=2, 2:2=1, 1+6=7}

Using not all numbers:

1. (8+6):2=7; {here 8+6=14, 14:2=7}

2. 6:2+4=7; {here 6:2=3, 3+4=7}

3. 42:6=7;

4. 28:4=7.

o-na [289]4 years ago
3 0
8 - (6-4) : 2 = 7
that's it
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Which of the following is not a property of a chi-square distribution?
laiz [17]

Answer:

c) Is not a property (hence (d) is not either)

Step-by-step explanation:

Remember that the chi square distribution with k degrees of freedom has this formula

\chi_k^2 = \matchal{N}_1^2 +  \matchal{N}_2^2 + ... + \, \matchal{N}_{k-1}^2 +  \matchal{N}_k^2

Where N₁ , N₂m .... N_k are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.

Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true

The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.

6 0
3 years ago
What is the total perimeter of the pitch and seating area?
natima [27]
1m = 100 cm

so
40 m = 4,000 cm
25 m = 2,500 cm
10 m = 1,000 cm

perimeter of big rectangle = 2(4,000 + 2000) = 12,000 cm
perimeter of small rectangle on the left: 2(2,500 + 800) = 6,600 cm
perimeter of small rectangle on the right: 2(1,000 + 800) = 3,600 cm
perimeter of circle = πd = 3.141593 x 200 = 628.32 cm

total area of the pitch and seating area :
=  12,000 + 6,600 + 3,600 + 628.32 = 22,828.32<span> cm

answer
</span>22,828.32 cm<span>

</span>
4 0
3 years ago
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In parallelogram ABCD, AB=18. Identify AD. HELP PLEASE!!
shutvik [7]

Answer:

Cannot be determined

Step-by-step explanation:

Both AD and BC could be any length

6 0
3 years ago
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