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allochka39001 [22]
3 years ago
10

Find the general solution for differential equation (D4 - 5D3 + 5D2 + 5D - 6)y = 0

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0
Given differential equation, (D<span>4 </span>- 5D3<span> + 5D</span>2<span> + 5D - 6)y = 0</span>

=> For general solution of equation,

Solve D<span>4 </span>- 5D3<span> + 5D</span>2<span> + 5D - 6 = 0</span>

=> D<span>4 </span>- 5D3<span> + 6D</span>2<span> - D</span><span>2 </span>+ 5D - 6 = 0

=> D2<span> (D</span>2<span> - 5D + 6) - (D</span>2<span> - 5D + 6) = 0</span>

=> (D2<span> - 5D + 6)(D</span>2<span> - 1) = 0           ................................(1)</span>

<span>Now </span>

D<span>2  </span><span>- 1 = (D - 1)(D + 1)  and </span>

Factors of D2<span> - 5D + 6</span>

D2<span> - 5D + 6 = D</span>2<span> - 2D - 3D + 6</span>

= D(D - 2) - 3(D - 2)

= (D - 3)(D - 2)

Therefore, equation (1) implies

(D2<span> - 5D + 6)(D</span>2<span> - 1) = (D - 3)(D - 2)(D - 1)(D + 1) = 0</span>

=> D = 3, 2, 1, -1 or D = -1, 1,, 2, 3

=> General solution of differential equation is,<span>

=><span> y = C1 e-x + C2 ex + C3 e2x + C4 e3x</span> .
</span>
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