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3 years ago

11

Find the surface area of the

1 answer:

katrin2010 [14]3 years ago

8 0

Answer:

the surface of hexagonal prism is 12 cm

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If the diagonal of a square is approximately 12.73, what is the length of its sides?

Alja [10]

Answer:

The length of the sides of the square is 9.0015

Step-by-step explanation:

Given

The diagonal of a square = 12.73

Required

The length of its side

Let the length and the diagonal of the square be represented by L and D, respectively.

So that

D = 12.73

The relationship between the diagonal and the length of a square is given by the Pythagoras theorem as follows:

$D^{2} = L^{2} + L^{2}$

Solving further, we have

$D^{2} = 2L^{2}$

Divide both sides by 2

$\frac{D^{2}}{2} = \frac{2L^{2}}{2}$

$\frac{D^{2}}{2} = L^2$

Take Square root of both sides

$\sqrt{\frac{D^{2}}{2}} = \sqrt{L^2}$

$\sqrt{\frac{D^{2}}{2}} = L$

Reorder

$L = \sqrt{\frac{D^{2}}{2}}$

Now, the value of L can be calculated by substituting 12.73 for D

$L = \sqrt{\frac{12.73^{2}}{2}}$

$L = \sqrt{\frac{162.0529}{2}}$

$L = \sqrt{{81.02645}$

$L = 9.001469325$

$L = 9.0015$ (Approximated)

Hence, the length of the sides of the square is approximately 9.0015

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3 years ago

Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three i

Arada [10]

Let n represent the interger l, the three consective intergers are represented by

$n$

$n + 2$

$n + 4$

The second one represent

$(n + 2) {}^{2} + 76 =( n + 4) {}^{2}$

Simplify both sides

$n {}^{2} + 4n + 4 + 76 = {n}^{2} + 8n + 16$

${n}^{2} + 4n + 4 = {n}^{2} + 8n - 60$

$4n + 4 = 8n - 60$

$4n + 64= 8n$

$64= 4n$

$n = 16$

The intergers are 16,18,20

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3 years ago

Here’s what I mean in my newest question

Arlecino [84]

38.5^2cm. i hope this helps you out

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