Wonderful! You gave us everything we could ever possibly want
to know, except the QUESTION. Fortunately, here at Brainly, we
have five Hogwarts drop-outs who work weekends for us as our
Department of Clairvoyance. When people post an intriguing
question but leave out some important part of it, our D of C can
usually fill in the missing part for us ... especially on weekends.
The question you left out is:
What is the next time that a red bus and a blue bus
will both leave the stadium together, simultaneously
and also both at the same time ?
Since red buses leave every 6 minutes starting at 4:00, and
blue buses leave every 8 minutes starting at 4:00, they both
leave simultaneously and also at the same time at minutes
after 4:00 that are common multiples of 6 and 8.
The least common multiple of 6 and 8 is 24 . After that,
every multiple of 24 is another common multiple of 6 and 8.
24 minutes is 4 red buses and 3 blue buses ... exactly !
A red bus and a blue bus will leave the stadium together at 4:24 .
After that, it will happen again at 24-minute intervals ... at 4:48,
5:12, 5:36, 6:00, . . . etc.
Answer:
C
Step-by-step explanation:
48/31 is already at its simplest form, however you can change it to a mixed fraction which would become 1 17/31
Answer:
When solving for x, answer = 
When solving for a, answer = 
Step-by-step explanation:
24 + 5x = -x + 6(5a - 4)
Start by multiplying 6 by the values in the parenthesis
24 + 5x = -x + 30a - 24
Add 24 to both sides of the equation
48 + 5x = -x + 30a
Add 1x to both sides of the equation
48 + 6x = 30a
Subtract 48 from both sides of the equation
6x = 30a - 48
Divide both sides of the equation by 6
x = 5a - 8 (Answer when solving for x)
Add 8 to both sides of the equation
x + 8 = 5a
Divide both sides of the equation by 5
a = 1/5x + 8/5 (Answer when solving for a)
-----------------------------------------
When solving for x, answer =
When solving for a, answer =
Hope this helps :)
It would be (all under a big square root) (-7-5)squared + (3+2) squared. This equals to about root 169
