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Lena [83]
3 years ago
5

How many solutions does the equation have? a+5=1/5(5a+25)

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0
A + 5 = \frac{1}{5} (5a + 25)

First, simplify \frac{1}{5} (5a + 25) to \frac{5a+25}{5} / Your problem should look like: a + 5 =  \frac{5a+25}{5}
Second, multiply both sides by 5. / Your problem should look like: 5a + 25 = 5(a + 5)
Third, expand to get rid of parenthesis. / Your problem should look like: 5a + 25 = 5a + 25
Fourth, both sides are equal, resulting it having infinite solutions.

Answer: infinite solutions

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make up an equation in the form of an y=kx +b, the graph which passes through the following points: (5,5) and (-10,-19)
Oksana_A [137]

Answer:

y = 8/5x - 3

Step-by-step explanation:

First, find the slope using rise over run (y2 - y1) / (x2 - x1)

(y2 - y1) / (x2 - x1)

(-19 - 5) / (-10 - 5)

-24 / -15

= 8/5

Plug in the slope and a given point into y = mx + b, and solve for b

y = mx + b

5 = 8/5(5) + b

5 = 8 + b

-3 = b

Plug in the slope and b into y = mx + b

y = 8/5x - 3

So, the equation is y = 8/5x - 3

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Answer:

-1, -1

Step-by-step explanation:

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You are studying the relationship between the history of early childhood trauma (categorized as trauma/no trauma) and weight in
jeka57 [31]

Answer:

You can decide to <u>reject</u> the Null Hypothesis at p < 0.05.

Step-by-step explanation:

In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.

The categories of childhood trauma are:

Trauma and No trauma.

So, number of rows is, <em>r</em> = 2.

The categories of weight in adulthood are:

Low to normal, Overweight, and Obese

So, number of columns is, <em>c</em> = 3.

The distribution of the statistic \chi^{2} is chi-square with (<em>r </em>- 1)(<em>c </em>- 1) degrees of freedom, where <em>r</em> represents the number of rows in the two-way table and <em>c</em> represents the number of columns.

Compute the degrees of freedom as follows:

df = (r-1)(c-1)=(2-1) \times (3-1) = 2

It is provided that the calculated value of Chi-square test statistic is 18.26.

Compute the <em>p</em>-value of the test as follows:

p-value=P(\chi^{2}_{2}\geq 18.26)\\=0.000108\\\approx0.00011

Decision rule:

The null hypothesis will be rejected if the <em>p</em>-value of the test is less than the significance level.

The significance level is, <em>α</em> = 0.05.

<em>p</em>-value = 0.00011 < <em>α</em> = 0.05.

The null hypothesis will be rejected at 5% level of significance.

Thus, the complete statement is:

"You can decide to <u>reject</u> the Null Hypothesis at p < 0.05."

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3 years ago
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