Answer:
• zero: -4, -4/3, 7
• positive: -4 < x < -4/3 . . . or 7 < x
• negative: x < -4 . . . or -4/3 < x < 7
Step-by-step explanation:
Zeros of the function are at x=-4, -4/3, +7. These are the values that make each of the individual factors be zero. For example, x-7=0 when x=7.
The function will be negative for x-values left of an odd number of zeros. It will be positive for x-values left of an even number of zeros (including left of no zeros, which is to say right of all zeros). This is because the sign of the factor giving rise to the zero changes for x-values on either side of that zero. (This is not true for zeros with even multiplicity, as the sign does not change at those.)
Answer: A
Step-by-step explanation
2.167x10^4 = 21,670
= 9,978
1.1x10^6
1100,000
= 56,344,000
2.468×10^5 = 246,800
Answer:
Step-by-step explanation:
The function used to represent the height of a punted football can be modeled as
f(x) = -.0079x² + 1.8x + 1.5
Where f(x) is the height in feet, and x is the horizontal distance, also in feet.
a) when the ball was punted, x = 0, therefore, the height of the punted ball would be
f(x) = -.0079(0)² + 1.8(0) + 1.5
f(x) = 1.5 feet
The height is 1.5 feet
b) The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height reached by the punted ball.
The vertex of the parabola is calculated as follows,
Vertex = -b/2a
From the equation,
a = - 0.0079
b = 1.8
Vertex = - - 1.8/0.0079 = 227.84 feet
So the maximum height of the punt is 227.84 feet
Answer:
C) 1/2(15 +23)(9)
Step-by-step explanation:
The formula for the area of a trapezoid in terms of base lengths b1 and b2 and height h is ...
... A = 1/2(b1 +b2)h
Substituting the values shown in the figure, this becomes ...
... A = 1/2(15 +23)(9) . . . . . matches selection C
