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Pani-rosa [81]
3 years ago
7

A transformation doubles each point's x-coordinate and leaves the point's y-coordinate intact. What will the transformation have

on the lenght?
Mathematics
1 answer:
g100num [7]3 years ago
7 0
It shouldn’t be any longer vertically so that should be your answer
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For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
Estimate then find the product 48x38
omeli [17]
1824 the estimate is 1820
4 0
3 years ago
Read 2 more answers
A zookeeper weighed an African elephant to be 9 × 103 pounds and an African lion to be 4 × 102 pounds. How many times greater is
amm1812

Answer:

The African Elephant is 2.27 times heavier than a African Lion.

Step-by-step explanation:

9 × 103 pounds = 927E.

4 × 102 pounds = 408L.

4 0
2 years ago
Read 2 more answers
the speed that a tsunami can travel is modeled by the equation mc025-1.jpg , where s is the speed in kilometers per hour and d i
Flura [38]
The answer is a.0.32 km.

The speed that a tsunami can travel is modeled by the equation is s = 356√d.

It is given:
s = 200 km/h
d = ?

Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562

Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32

Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
5 0
3 years ago
Read 2 more answers
Help me please and thx
Olenka [21]
Y = kx, so y/x is constant

you want y such that
y/12 = -2/-8
3 0
2 years ago
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