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Pani-rosa [81]
3 years ago
7

A transformation doubles each point's x-coordinate and leaves the point's y-coordinate intact. What will the transformation have

on the lenght?
Mathematics
1 answer:
g100num [7]3 years ago
7 0
It shouldn’t be any longer vertically so that should be your answer
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The side length of a cube is √7 cm.
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<span>The answer is The total area of the top and bottom squares. s = √7 cm is irrational value and we need rational value. Let's check all choices: A. The volume. V = (s)^3. If s = √7, V = (√7)^3 = 7√7 - irrational value. B. The perimeter of the front square. P = 4 * s = 4 * √7 = 4√7 - irrational value. C. The diagonal of the back square. d = s√2 = √7 * √2 = √(7*2) = √14 - irrational value. D. The total area of the top and bottom squares. A = 2 * s^2 = 2 * (√7)^2 = 2 * 7 = 14 - rational value.</span>
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<u>Question 15 Answer:</u> In this sentence, I will show how to print out a statement any number of times you want in Python. So, basically, to do this, we are going to use a for loop with the keyword range in the statement. Using this method, we can print out a statement any number of times we want by specifying that number in the range () function.

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2 years ago
A new car is purchased for 20000 dollars. The value of the car depreciates at 12. 5% per year. What will the value of the car be
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To solve the problem we need to know about depreciation.

<h2>Formula of Depreciation</h2>

The formula of depreciation is given as,

A = P(1-r)^t

where,

A is the value of an object after t years of time,

P is the value of the object at the beginning, and

r is the rate of depreciation.

The value of the car after 11 years is $4,603.81.

<h2>Explanation</h2>

Given to us

  • Cost of Car at the beginning, p = $20,000
  • Rate of depreciation, r = 12.5%
  • Time, t = 11 years

<h3>Value of the car after 11 years</h3>

Substituting the values in the formula of depreciation,

A = P(1-r)^t

Value of the car after 11 years = P(1-r)^n

                                                 = \$20,000(1-0.125)^{11}\\\\&#10;= \$20,000\times 0.23\\\\&#10;= \$4,603.822 \approx \$4,603.81

Hence, the value of the car after 11 years is $4,603.81.

Learn more about Depreciation:

brainly.com/question/3023490

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