Answer: 23 is your answer
Step-by-step explanation:
Answer:
Equation is: y = 0.5x² + 0.5x - 3
Explanation:
general form of the parabola is:
y = ax² + bx + c
Now, we will need to solve for a, b and c.
To do this, we will simply get points from the graph, substitute in the general equation and solve for the missing coefficients.
First point that we will use is (0,-3).
y = y = ax² + bx + c
-3 = a(0)² + b(0) + c
c = -3
The equation now becomes:
y = ax² + bx - 3
The second point that we will use is (2,0):
y = ax² + bx - 3
0 = a(2)² + b(2) - 3
0 = 4a + 2b -3
4a + 2b = 3
This means that:
2b = 3 - 4a
b = 1.5 - 2a ...........> I
The third point that we will use is (-3,0):
y = ax² + bx - 3
0 = a(-3)² + b(-3) - 3
0 = 9a - 3b - 3
9a - 3b = 3 ...........> II
Substitute with I in II and solve for a as follows:
9a - 3b = 3
9a - 3(1.5 - 2a) = 3
9a - 4.5 + 6a = 3
15a = 7.5
a = 7.5 / 15
a = 0.5
Substitute with the value of a in equation I to get b as follows:
b = 1.5 - 2a
b = 1.5 - 2(0.5)
b = 0.5
Substitute with a and b in the equation as follows:
y = 0.5x² + 0.5x - 3
Hope this helps :)
Answer:
AM = 25, AC = 15, CM = 20
Step-by-step explanation:
The given parameters are;
In ΔACM, ∠C = 90°, 
⊥ 
, AP = 9, and PM = 16
² + 
² = ²
= 
+ PM = 9 + 16 = 25
= 25
² = ² + ² = 9² + ²
∴ ² = 9² + ²
Similarly we get;
² = 16² + ²
Therefore, we get;
² + ² = 9² + ² + 16² + ² = ² = 25²
2·² = 25² - (9² + 16²) = 288
² = 288/2 = 144
= √144 = 12
From ² = 9² + ², we get
= √(9² + 12²) = 15
= 15
From, ² = 16² + ², we get;
= √(16² + 12²) = 20
= 20.
Answer:
-1/2
Step-by-step explanation:
just trust me, idk how to explain it
Answer:
C = 75 in
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Assume that the height of all people follows a normal distribution with a mean of 69 in and a standard deviation of 2.9 in.
This means that 
Calculate the cut-off height (C) that ensures only people within the top 2.5% height bracket are allowed into the team.
This is the 100 - 2.5 = 97.5th percentile, which is X when Z has a pvalue of 0.975, so X when Z = 1.96.
Rounded to the nearest inch,
C = 75 in
