Y - 6 = -3/7(x + 5)
y - 42/7 = -3/7x - 15/7
y = -3/7x + 27/7
A line that is tangent to each of the two coplanar circles
Answer:
DB = 24
Step-by-step explanation:
First, note that the diagonals of a rectangle are equal and bisect each other. In other words, DB = CA and CE = EA and DE = BE.
Also, AE + CE = CA
So, using this, we can write this equation:
AE = CE
x + 4 = 3x -12
Subtract 4 from both sides.
x = 3x -16
Subtract 3x from both sides.
-2x = -16
Divide both sides by -2
x = 8
Then, substitute this into AE + CE = CA
x + 4 + 3x - 12 =
8 + 4 + 24 - 12 = 24
Then, because CA = DB,
DB = 24
I hope this helps! Feel free to ask any questions! :)
Answer:
(-1, 1)
Step-by-step explanation:
Midpoint formula: (x₁ + x₂/2 , y₁ + y₂/2)
Substitute the values into the formula.
(-5 + 3/2 , 3 - 1/2)
(-2/2 , 2/2)
(-1,1)
Therefore, the midpoint is (-1, 1).
Insert x + 3 instead of x into the equation of the function f(x):
f(x) = 3 - 6x²
f(x + 3) = 3 - 6(x + 3)²
use (a + b)² = a² + 2ab + b²
= 3 - 6(x² + 2(x)(3) + 3²) = 3 - 6(x² + 6x + 9)
use distributive property
= 3 + (-6)(x²) + (-6)(6x) + (-6)(9) = 3 - 6x² - 36x - 54
combine like terms
= -6x² - 36x - 51
<h3>Answer: f(x + 3) = -6x² - 36x - 51</h3>
