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4 years ago

For a 180° rotation about the origin, write the coordinates of each point in the table.

Mathematics

1 answer:

Marta_Voda [28]4 years ago

7 0

Answer:

Hey, you don't include any points, but I can give you the rule for an 180 degree rotation.

You just need to write the same points, but negative. So going from (x,y) to

(-x,-y).

As an example let's say you wanted to rotate (3,-4) 180 degrees about the origin. The the point after the rotation would be (-3,4).

Hope that helps!

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If the sin 90° = 1, then the cos 0° = _____. (1 point)

Cloud [144]

sin 90° = 1

cos 0° = 1

There's a simple formula : sin θ = cos (90°- θ) or cos θ = sin (90°- θ) 

So : cos 0° = sin (90° - 0°) = sin 90° = 1

7 0

3 years ago

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(Do not use spaces. Use to represent exponents. Example 2^3 is 22.)

Alik [6]

Answer: y=6^x-3

It is a exponent form of graph, so first:

y=a^x-b

When b=0, the asymptote is y=0 but as the asymptote given is y=-3, b=-3

Second:

the y value increases 6, when x changes 0 to 1, so a=6

8 0

3 years ago

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Picking a month of the year in the day of the week (fundamental counting principle)

inysia [295]

Since you mentioned the fundamental counting principle, I assume you are looking for the total number of possibilities.

If you are picking a month, there are 12 options.
If you are selecting a day of the week, there are 7 options.

If you are doing both, you multiply the two numbers together.
12 x 7 = 84

8 0

4 years ago

Abigail has 16 shoes use repeated subtraction to show how many pairs of shoes Abigail has

erik [133]

Hello!

Here is how we solve this question.

We know that 2 shoes = 1 pair

So we subtract 2 from 16 until we reach 0, and count how many times we subtracted.

16-2=14

14-2=12

12-2=10

10-2=8

8-2=6

6-2=4

4-2=2

2-2=0

After we do repeated subtraction we find that Abigail has 8 pairs of shoes!

Hope this helps you with your question.

7 0

3 years ago

Members of the millennial generation are continuing to be dependent on their parents (either living with or otherwise receiving

Morgarella [4.7K]

Answer:

$\bf H_0:$ The mean of adults aged 18 to 32 that continue to be dependent on their parents is 0.3

$\bf H_a:$ The mean of adults aged 18 to 32 that continue to be dependent on their parents is greater than 0.3

b) 34%

c) practically 0

d) Reject the null hypothesis.

Step-by-step explanation:

Since an individual aged 18 to 32 either continues to be dependent on their parents or not, this situation follows a Binomial Distribution and, according to the previous research, the probability p of “success” (depend on their parents) is 0.3 (30%) and the probability of failure q = 0.7

According to the sample, p seems to be 0.34 and q=0.66

To see if we can approximate this distribution with a Normal one, we must check that is not too skewed; this can be done by checking that np ≥ 5 and nq ≥ 5, where n is the sample size (400), which is evident.

We can then, approximate our Binomial with a Normal with mean

$\bf np = 400*0.34 = 136$

and standard deviation

$\bf \sqrt{npq}=\sqrt{400*0.34*0.66}=9.4742$

Since in the current research 136 out of 400 individuals (34%) showed to be continuing dependent on their parents:

$\bf H_0:$ The mean of adults aged 18 to 32 that continue to be dependent on their parents is 0.3

$\bf H_a:$ The mean of adults aged 18 to 32 that continue to be dependent on their parents is greater than 0.3

So, this is a right-tailed hypothesis testing.

According to the sample the proportion of "millennials" that are continuing to be dependent on their parents is 0.34 or 34%

Our level of significance is 0.05, so we are looking for a value $\bf Z^*$ such that the area under the Normal curve to the right of $\bf Z^*$ is ≤ 0.05

This value can be found by using a table or the computer and is $\bf Z^*$ = 1.645

Applying the continuity correction factor (this should be done because we are approximating a discrete distribution (Binomial) with a continuous one (Normal)), we simply add 0.5 to this value and

$\bf Z^*$ corrected is 2.145

Now we compute the z-score corresponding to the sample

$\bf z=\frac{\bar x -\mu}{s/\sqrt{n}}$