The answer is (2,-6) look at the picture to see how to do it
Answer:
Hence, Grasshopper will land on the ground after 1.5 sec.
Step-by-step explanation:
It s given that:
The height, in feet, of the grasshopper above the ground after t seconds is modeled by the function:
Now we are asked to find:
In how many seconds will the grasshopper land on the ground?
i.e. we have to find the value of t such that h(t)=0
i.e.
i.e. we need to find the roots of the given quadratic equation.
On solving the quadratic equation or plotting it's graph we could observe that the point where h(t)=0 are:
As time can't be negative hence we will consider:
Hence, grasshopper will land on the ground after 1.5 sec.
Answer: a) 46 minutes
b) 10:47
The basic knowledge for this is that 60 minutes = 1 hour
<u>a)</u> Question a asks for how long it took from a 10:34 bus from Mosley to reach Bamford. From the table you can see that the 10:34 bus reaches Bamford at 11:20. All you have to do is count from 10:34 to 11:20.
10:34 will become 11:00 at 10:60 right? Clock's generally don't show 10:60 but goes directly to 11:00 after 1 minute is passed at 10:59. So from 10:34 to 11:00, it takes 26 minutes. Remember the bus reaches at 11:20 so from 11:00 to 11:20, it takes 20 minutes. Now add them up:
26 minutes + 20 minutes = 46 minutes
Here you go! Total 46 minutes from Mosley to Bamford.
<u>b)</u> From question b, we can see that Trina did not ride the first bus or by any chance missed it because the bus left at 10:14 and she is at the station at 10:15. Now think it from your perspective! You missed the first bus and you are in a big rush. So to reach your destination as early as possible, you will obviously take the next earliest bus. The next bus is at 10:24 (Belton). So if we take the 10:24 bus in Belton, it reaches at 10:47 in Garton.
∩_∩
(„• ֊ •„)♡
┏━∪∪━━━━┓
hope it helped
┗━━━━━━━┛
240 is the answer to your question just multiply them
Convert to vertex form:-
y = 5(x^2 - 2x) + 1
y = 5[(x - 1)^2 - 1] + 1
y = 5(x - 1)^2 - 4
vertex is (1, -4)
