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3 years ago

I need help on math whats 10x3x12x21

Mathematics

2 answers:

insens350 [35]3 years ago

7 0

Answer:

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Step-by-step explanation:

ᵇʳᵃⁱⁿˡʸ.ᵗᵒᵈᵃʸ

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motikmotik3 years ago

4 0

Answer:

7560

Step-by-step explanation:

You might be interested in

If y=8 when x =3 find try when x=45

grin007 [14]

Fist of all, y = 8 and x = 3 is more likely to be understood as a ratio. So for the rest of the answer, their relationship would be represented as y:x

Thus: y:x = 8:3

The problem would be finding y when x = 45

Let us proceed on using the previous equation and substitute x with 45 which would look like this:

y:45 = 8:3

Ratios can also be expressed as fractions which would make things more understandable and easy to solve. So the new form of our equation would be like this:

y/45 = 8/3

Then we proceed with a cross multiplication where the equation becomes like as what is shown below:

3y = 45 * 8

From there, you can solve it by multiplying 45 and 8 then dividing the product with 3 to get y

3y = 360

y = 120

Another way of looking at the problem, especially problems like these, is to take the whole question or statement as an equation. it would probably look like this:

y = 8 when x = 3 : y = ? when x = 45

This would make you understand what approach you can use to solve the given problem.

6 0

4 years ago

Answer this correctly for brainliest pls!!

Molodets [167]

A function that depicts depreciation can be represented as equations, graphs and tables.

<h3>The yearly value of each car for the first five years</h3>

The functions are given as:

$V(t) =C(1 - r^t)$

$V(t) =C(1 - r)^t$

Where:

C = 5895 --- the initial value of the car

r = 22% --- the rate of depreciation

For the first 5 years, the values of t = 1, 2, 3, 4 and 5

For the first function, we have:

$V(1) =5895(1 - 22\%^1) = 4598.1$

$V(2) =5895(1 - 22\%^2) = 5609.7$

$V(3) =5895(1 - 22\%^3) = 5832.2$

$V(4) =5895(1 - 22\%^4) = 5881.2$

$V(5) =5895(1 - 22\%^5) = 5892.0$

For the second function, we have

$V(1) =5895(1 - 22\%)^1 = 4598.1$

$V(2) =5895(1 - 22\%)^2 = 3586.5$

$V(3) =5895(1 - 22\%)^3 = 2797.5$

$V(4) =5895(1 - 22\%)^4 =2182.0$

$V(5) =5895(1 - 22\%)^5 = 1702.0$

So, the table of values is:

$\left[\begin{array}{ccc}Years&Car\ 1&Car\ 2\\1&4598.1&4598.1\\2&5609.7&3586.5\\3&5832.2&2797.5\\4&5881.2&2182.0\\5&5892.0&1702.0\end{array}\right]$

See attachment for the graphs of the two functions

<h3>Interpreting the graphs</h3>

The graph of car 1 increases up to C(t) = 5895, and then remains constant as the value of t increases while the graph of car 2 follows an exponential pattern.

This means that, the graph 2 that follows an exponential pattern is more realistic

<h3>The worth of the cars after 5 years</h3>

From the table, the worth of car 1 is $5892.0, while the worth of car 1 is $1702.0

Read more about graphs and functions at:

brainly.com/question/13473114

5 0

2 years ago

Over 30 points please help me i need it bad

pashok25 [27]

Distance formula: d= square root of (x2-x1)^2+(y2-y1)^2
(3,5) (7,3)
d= square root of (7-3)^2+(3-5)^2
d= square root of (4^2)+(-2^2)
d= square root of 16+4
d= square root of 20
d=4.47...rounded= 4.5
Hope this helped!

6 0

3 years ago

Given the function f(x)= x^4+6x^3-x^2-30x+4

Romashka-Z-Leto [24]

The correct answers are a,b,e,f

7 0

4 years ago

2 minutes left, quick question:

rodikova [14]

Answer:

Step-by-step explanation

Drawing quadrilateral ABCD (in picture), I tried to prove that the triangles ABD CDB were congruent, proving that the quadrilateral was a parallelogram, however, with the terms you just described, it is impossible prove that the triangles were congruent as SSA is not a valid congruence postulate. Therefore, ABCD does not have to be a parallelogram.

6 0

3 years ago