Answer:
Explanation:
Let y amount be invested in bonds
Let x amount be invested in money account
Let x amount be invested in stocks
x = y + 3x
10,000 = 12/100(y+3x) + 8/100*y + 4/100*x
10,000 = 12(y+3x) + 8y + 4x / 100
10,000 * 100 = 12y+36x + 8y + 4x
2500 * 100 = 3y + 9x + 2y + x
250,000 = 5y + 10x
50,000 = y + 2x.......................(1)
x + y + z = $100,000
y + 3x + y + x = $100,000
2y + 4x = 100,000
y + 2x = 50,000.......................(ii)
y = 50,000 - 2x
x = 50,000 + x
z = z
<u>2 Options are</u>
{(x,y,x), (x2,y2,z2)}
= (50000, 50000) (60000, 30000, 10000)
