Answer: y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2
Step-by-step explanation:
vertex form is y=a(x-h)^2 + k
here we can see the vertex is (3,0) which is (x,y). Or (h,k) in this case.
so to plug that into vertex form, we now have y=a(x-3)^2 + 0. or just y=a(x-3)^2.
now we need to find "a" which is the leading coefficient. to do that we can plug in the (6,-6) for the x and y parts of the above equation. so we'd have
-6=a(6-3)^2. which goes to -6=a(2)^2 which is -6=4a. divide each side by 4 to get a = -2/3. plug this in for a
the final equation would be y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2
Answer: 250 m
Step-by-step explanation:
Given
Distance between Ursula and Velda house is 4 km or 4000 m
Ursula walks at the rate of
Velda walks at the rate of
Time taken by them to cover 4000 m is
Distance covered by them 15 min before they meet
Ursula
Velda
The total length covered by them is
They are apart before they meet
Answer:
The answer is C.
Step-by-step explanation:
<u>Answer:</u>
The length of VI = 4 cm
<u>Solution:
</u>
The plot is like a quadrilateral and the fences are built on the diagonal
We know that for quadrilateral both the diagonals are in same height,
So as per the picture, GH = FI
Now we know that GV = 6.55, FV = 5.84, VH = 3.27
Hence,
GH = FI
<u><em>Rounding off:
</em></u>
- If the number that we are rounding is<em> followed by 5 to 9</em>, then the number has to be <em>increased to the next successive number</em>.
- If the number that we are rounding is <em>followed by 1 to 4</em>, then the number has to <em>remain the same</em>.
Here the number to be round off is 3.98, 9 belongs to the first category stated above. So, 3 is increased to 4.
Hence, the length of VI = 4 cm.
Answer:
7
Step-by-step explanation:
Just notice that correct answers are whole numbers.
And, to win the game,Maria must have a score less than -80, it means she needs to score al least -85 ( it can not be -81, -82.. because 1 correct answer score -5, only multiples of -5 are accepted)
So, we take: = 7 correct answers to win the game.
Hope it will find you well.