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3 years ago

What is 7x =90+22 ?

Mathematics

2 answers:

Elanso [62]3 years ago

8 0

Answer:

x=16

Step-by-step explanation:

Marrrta [24]3 years ago

5 0

Answer:

x=16

Step-by-step explanation:

7x=90+22

7x=112

x=16

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Put the numbers in value order. Than look for the most often number, that will be the mode. In this case, 73 is the mode.

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Nadusha1986 [10]

Points that lie on the same line are called collinear points

Collinear points are points that lie along a straight line or along the same line.

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1 year ago

What is the value of x? Enter your answer in the box.

Radda [10]

Answer:

x = 8

y = 6

Step-by-step explanation:

First and foremost, it's an equilateral triangle, therefore all sides and angles are equal.

Knowing that the sum of angle in a triangle is 180°, therefore each angle is 60°.

Then equating (7x+4)° to 60, we have that,

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2 years ago

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3 years ago

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Determine if the set of polynomials {x^2 –2x+1, 2x² + 3x -4,-x2+x+5) is a linearly independent set in P2. Is it a basis for P? W

WITCHER [35]

Answer with Step-by-step explanation:

We are given that a set of polynomials ${x^2-2x+1,2x^2+3x-4,-x^2+x+5}$

We have to find that given set is a linearly independent set in $P_2$

and given set is a basis for $P_2$ or not.

Matrix of given set of polynomials

A= $\left[\begin{array}{ccc}1&-2&1\\2&3&-4\\-1&1&5\end{array}\right]$

Linearly Independent set :If any row or any column is not a linear combination of other rows or columns then the set is linearly independent set.

Any row or column is not a linear combination of other rows or columns.Therefore, given set is a linearly independent set .

We know that

$P_2=x^2$

Element of $P_2$ is of the form

$ax^2+bx+c$

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Hence, given set is linearly independent in $p_2$ .

If any set is basis for any vector space then it satisfied the following two conditions

1.Given set is linearly independent.

2.Every element of given vector space spanned by the given set.

Given set of polynomials are linearly independent and spanned every element of $P_2$ .

Therefore, given set is as basis for $p_2$ because the set is linearly independent and spanned $P_2$ .

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3 years ago