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SpyIntel [72]
3 years ago
9

Explain how you would complete the translation of an exponential function using the mapping statement f(x)→f(x+k1)+k2. Does it m

atter which direction is translated first? Why or why not? Give examples to support your answer
Mathematics
1 answer:
Ronch [10]3 years ago
3 0
First, in the exponent, substitute x by x+k1. Then add k2.

The order in which you apply the translations is not important. When you substitute x by x+k1, you are translating the function horizontally to the left k1 units. When you add k2, you are translating the function vertically up k2 units. Obviously, the order is nor important.

Example:

Let f(x)=2^x, k1=3, and k2=4.

Substitute x by x+3:

f(x)=2^x \rightarrow f(x+3)=2^{x+3}

Add 4:

f(x+3)=2^{x+3} \rightarrow f(x+3)+4=2^{x+3}+4

In reverse order:

Add 4:

f(x)=2^x \rightarrow f(x)+4=2^x+4

Substitute x by x+3:

f(x)+4=2^x+4 \rightarrow f(x+3)+4=2^{x+3}+4
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. Suppose the weight of Chipotle burritos follows a normal distribution with mean of 450 grams, and variance of 100 grams2 . Def
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Complete Question

Suppose the weight of Chipotle burritos follows a normal distribution with mean of 450 grams, and variance of 100 grams2 . Define a random variable to be the weight of a randomly chosen burrito.

(a) What is the probability that a Chipotle burrito weighs less than 445 grams? (3 points)

(b) 20% of Chipotle burritos weigh more than what weight

Answer:

a

   P(X  <  445  )=  0.3085

b

  k = 458.42

Step-by-step explanation:

From question we are told that

     The population mean is \mu  =  450 \ g

      The variance is var =  100 \ g^2

      The  consider weight is  x =  445 \ g

The  standard deviation is mathematically represented as

     \sigma  = \sqrt{var}

substituting values

     \sigma  = \sqrt{ 100}

     \sigma  = 10

Given that weight of Chipotle burritos follows a normal distribution the  the probability that a Chipotle burrito weighs less than x grams is mathematically represented as

        P(X  <  x  ) =  P ( \frac{X  -  \mu }{\sigma }  < \frac{x  -  \mu }{\sigma }  )

Where  \frac{X - \mu }{\sigma } is  equal to z (the standardized values of the random number X )

So

     P(X  <  x  ) =  P (Z  < \frac{x  -  \mu }{\sigma }  )

substituting values

     P(X  <  445  ) =  P (Z  < \frac{445  -  450 }{10}  )

      P(X  <  445  ) =  P (Z

Now from the normal distribution table  the value for P (Z  is  

      P(X  <  445  ) =  P (Z

=>   P(X  <  445  )=  0.3085

Let the  probability  of the Chipotle burritos weighting more that k be 20% so  

       P(X  >  k  ) =  P ( \frac{X  -  \mu }{\sigma }  > \frac{k  -  \mu }{\sigma }  ) = 0.2

=>    P (Z> \frac{k  -  \mu }{\sigma }  ) = 0.2

=>    P (Z> \frac{k  -  450}{10 }  ) = 0.2

From the normal distribution table the value of z  for  P (Z> \frac{k  -  \mu }{\sigma }  ) = 0.2 is  

    z  =  0.8416

=>   \frac{k  -  450}{10 }  = 0.8416

=>   k = 458.42

       

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Answer:

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