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4 years ago

How do I solve log(x) - log(6) = 2 ?

1 answer:

8 0

$\bf \textit{Logarithm Cancellation Rules}
\\\\
log_a a^x = x\qquad \qquad \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{a^{log_a x}=x}
\\\\\\
\textit{Logarithm of rationals}
\\\\
log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y)
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
log(x)-log(6)=2\implies log\left(\cfrac{x}{6} \right)=2\implies log_{10}\left(\cfrac{x}{6} \right)=2
\\\\\\
10^{log_{10}\left(\frac{x}{6} \right)}=10^2\implies \cfrac{x}{6}=10^2\implies x=600$

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Find the radius of a cylinder with volume 351.9 cubic cm and height 7 cm.

Finger [1]

Answer:

Step-by-step explanation:

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3 years ago

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Polygons are a subcategory of parallograms

dolphi86 [110]

Answer:

Step-by-step explanation:

Category:Parallelograms. ... A parallelogram is a quadrilateral whose opposite sides are parallel to each other, and whose sides may or may not all be the same length.

We know many quadrilaterals by their special shapes and properties, like squares. Remember, if you see the word quadrilateral, it does not necessarily mean a figure with special properties like a square or rectangle! In word problems, be careful not to assume that a quadrilateral has parallel sides or equal sides unless that is stated.

Special Quadrilaterals

A parallelogram has two parallel pairs of opposite sides.

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A rhombus is defined as a parallelogram with four equal sides. Is a rhombus always a rectangle? No, because a rhombus does not have to have 4 right angles.

Trapezoids only have one pair of parallel sides. It's a type of quadrilateral that is not a parallelogram. (British name: Trapezium)

Kites have two pairs of adjacent sides that are equal.

We can use a Venn diagram to help us group the types of quadrilaterals.

A Venn diagram uses overlapping circles to show relationships between groups of objects. All "quadrilaterals" can be separated into three sub-groups: general quadrilaterals, parallelograms and trapezoids.

Is a rectangle always a rhombus? No, because all four sides of a rectangle don't have to be equal. However, the sets of rectangles and rhombuses do intersect, and their intersection is the set of squares—all squares are both a rectangle and a rhombus.

We can put squares in the intersection of the two circles.

From this diagram, you can see that a square is a quadrilateral, a parallelogram, a rectangle, and a rhombus!

Is a trapezoid a parallelogram? No, because a trapezoid has only one pair of parallel sides. That is why we must show the set of trapezoids in a separate circle on the Venn diagram.

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Related Links:

Area Formulas

Perimeter Formulas

Homework Help | Geometry | Polygons Email this page to a friend Email this page to a friend

· Polygon basics

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8 0

3 years ago

6 + 3(x+4) PLEASEEE I NEED HELP

Ksivusya [100]

i'm going to assume you're supposed to solve for x

Answer:

x = -2

Step-by-step explanation:

so you're trying to get x out of the equation and by it self

i would start this off by setting the equation equal to 0

then subtract 6

i would then divide by 3 on each side

you should then have x+4=2

you then subtract 4 to cancel it out

you then get your answer of x = -2

hope this helps and lmk if you have questions!! <3

5 0

3 years ago

Of all customers purchasing automatic garage-door openers, 75% purchase Swedish model. Let X = the number among the next 15 purc

Lelechka [254]

Answer:

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = 0.2737

d) μ = 15*0.75 = 11.25. σ² = 11.25*0.25 = 2.8125

Step-by-step explanation:

X is a binomial random variable with parameters n = 15, p = 0.75. Therefore

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

P(X>10) = P(X=11) + P(X=12)+ P(X=13)+P(X=14)+P(x=15)

$P(X=11) = {15 \choose 11} * 0.75^{11} * 0.25^4 = 0.2252$

$P(X=12) = {15 \choose 12} * 0.75^{12} * 0.25^3 = 0.2252$

$P(X=13) = {15 \choose 13} * 0.75^{13} * 0.25^2 = 0.1559$

$P(X=14) = {15 \choose 14} * 0.75^{14} * 0.25 = 0.0668$

$P(X=15) = {15 \choose 15} * 0.75^{15} = 0.0134$

Thus,

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = P(X = 6) + P(X = 7) + P(X = 8) + P(X=9) + P(X=10)

$P(X=6) = {15 \choose 6} * 0.75^{6} * 0.25^9 = 0.0034$

$P(X=7) = {15 \choose 7} * 0.75^{7} * 0.25^8 = 0.0131$

$P(X=8) = {15 \choose 8} * 0.75^{8} * 0.25^7 = 0.0393$

$P(X=9) = {15 \choose 9} * 0.75^{9} * 0.25^6 = 0.0918$

$P(X=10) = {15 \choose 10} * 0.75^{10} * 0.25^{5} = 0.1652$

Thereofre,

$P(6 \leq X \leq 10) = 0.0034 + 0.0134 + 0.0393 + 0.0918 + 0.1652 = 0.2737$

d) μ = n*p = 15*0.75 = 11.25

σ² = np(1-p) = 11.25*0.25 = 2.8125

3 0

3 years ago

Please help, brainliest, thanks, five star

AnnZ [28]

Answer:

2(3x + 4)

Step-by-step explanation:

2 x 3x = 6x and 2 x 4 = 8

7 0

3 years ago