Not only you're gonna divide 8 by -3 for some reason, but you also divide all terms by -3. For instance,
(-3y = -2x + 8) / -3
(-3/-3)y = (-2/-3)x + 8/-3
y = (2/3)x - 8/3

Hope this helps.

3 0

3 years ago

Solve the rational equation x divided by 6 equals x squared divided by quantity x minus 1 end quantity, and check for extraneous

Dmitriy789 [7]

Answer:

Solution: $x=-\frac{1}{5}$ , $x=0$

Step-by-step explanation:

Given:

The rational equation to solve is given as:

$\frac{x}{6}=\frac{x^2}{x-1}$

Doing cross product, we get:

$x\times (x-1)=6\times x^2\\x^2-x=6x^2\\\textrm{Bringing all variables to the right side, we get:}\\6x^2-x^2+x=0\\5x^2+x=0\\x(5x+1)=0\\x=0\ or\ 5x+1=0\\x=0\ or\ x=-\frac{1}{5}$

Now, for $x=0$ , the rational equation is equal to 0. So, $x=0$ is a solution.

Also, $x=-\frac{1}{5}$ is also a solution.

So, no extraneous solution.

4 0

3 years ago