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Margarita [4]
3 years ago
13

If the radius of a circle is 75 hundredths of a meter, what is the diameter?

Mathematics
1 answer:
givi [52]3 years ago
5 0
We know that the diameter of a circle is 2 times the radius.

If the radius is 0.75 meters, then the diameter must be 2 x 0.75 meters = 1.5meters 
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Question 2.what is the probability that between 80 and 115 complaints are received in one week? use a n(110,20) model to approxi
AURORKA [14]

Calculate standard  Z values for the given data:-

z = (80 - 110) / 20 = - 3/2 = -1.5

and z = (115 - 110) / 20 =  0.25

so we need  Prob ( -1.5 < z < 0.25)

Using standard tables this  comes to 0.5319  Answer


6 0
3 years ago
Derive the equation of the parabola with the focus <br> is (-7,5) and the directrix of y=-11
Volgvan
So, notice, the focus point is at -7, 5, and the directrix is at y = -11.

keep in mind that the vertex is half-way between those two fellows, and the distance from the vertex to either one of them is "p" units, check the picture below.

with that focus point and that directrix, the half-way over the axis of symmetry will be -7, -3, that's where the vertex is at, and notice the distance "p", is 8 units.

since the parabola is opening upwards, "p" is positive 8.

\bf \textit{parabola vertex form with focus point distance}\\\\&#10;\begin{array}{llll}&#10;4p(x- h)=(y- k)^2&#10;\\\\&#10;\boxed{4p(y- k)=(x- h)^2}&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ( h, k)\\\\&#10; p=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;h=-7\\&#10;k=-3\\&#10;p=8&#10;\end{cases}\implies 4(8)[y-(-3)]=[x-(-7)]^2&#10;\\\\\\&#10;32(y+3)=(x+7)^2\implies y+3=\cfrac{1}{32}(x+7)^2&#10;\\\\\\&#10;y=\cfrac{1}{32}(x+7)^2-3

8 0
3 years ago
Use Cramer's rule to solve 4x + 3y = 4, -3x - y = 7. Show your work.
nikklg [1K]
The answer is shown in the picture because it ran afoul of Brainly's "bad word" detector.

3 0
3 years ago
Write expression using a positive exponent&lt;br /&gt;
GrogVix [38]

a^{-n}=\dfrac{1}{a^n}\\\\4^{-1}=\dfrac{1}{4}\\\\5^{-3}=\dfrac{1}{5^3}\\\\-6^{-2}=-\dfrac{1}{6^2}\\\\-3^{-3}=-\dfrac{1}{3^3}\\\\3^{-5}=\dfrac{1}{3^5}\\\\10^{-4}=\dfrac{1}{10^4}\\\\p^{-1}=\dfrac{1}{p^1}\\\\a^{-10}=\dfrac{1}{a^{10}}\\\\d^{-3}=\dfrac{1}{d^3}\\\\q^{-4}=\dfrac{1}{q^4}\\\\b^{-15}=\dfrac{1}{b^{15}}\\\\r^{-20}=\dfrac{1}{r^{20}}

4 0
3 years ago
Will mark brainly!
ch4aika [34]

Answer:

{f}^{ - 1} (x) =  \frac{2}{x - 6}  + 1

Step-by-step explanation:

we will subistitute f(x) by y and solve the equation in order to get the value of x,

then we subistitute x by y and y by x and y=f^-1(x)

8 0
2 years ago
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